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nignag [31]
3 years ago
6

An exam has two probability problems, 1 and 2. If 37% of the students solved problem 1 and 12% of the students solved both probl

ems 1 and 2, what is the percent of students who solved problem 2 given that they solved problem 1? A) 4% B) 25% C) 32% D) 69%
Mathematics
1 answer:
Zanzabum3 years ago
8 0

Answer:

about 32%

Step-by-step explanation:

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The mean of Alice's last 5 math test scores is 88. The first 4 of these 5 math test scores were 87, 75, 93, and 85. What score d
stiks02 [169]

Answer:

Step-by-step explanation:

x is the score she got on the fifth test.

Since her average score is 88, the sum of all five tests is 5×88.

x + 87 + 75 + 93 + 85 = 5×88 = 440

x = 440 -  87 - 75 - 93 - 85

x = 100

She got a 100 on her fifth test.

6 0
2 years ago
Wanda wants to buy a pair of shoes that cost $48 if sales tax is 8.25% what will be the total cost
lidiya [134]
48 x 8.25% = 3.96
Now add 3.96 + 48
Answer 51.96
3 0
3 years ago
Write a number as a cube 1/64​
butalik [34]

Answer: Cube root of 64 in radical form: ∛64.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The two tables give the number of pints of red and blue paint that are used to make different amounts of two shades of purple pa
kirza4 [7]

The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.

This means that Purple #1 is <u>a redder</u> shade of purple than Purple #2.

Purple #2 is <u>a bluer</u> shade of purple than Purple #1.

Step-by-step explanation:

The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.

  • Making blue's quantity as 3 parts for purple #1 implies red part becomes 1.5 to maintain the ratio 1:2
  • Purple #1 has 1/3 parts red and 2/3 parts blue. Purple #2 has 1/4th part red and 3/4th part blue.
  • Hence, Purple #1 is <u>a redder</u> shade of purple than Purple #2.
  • From the above explanation, Purple #2 is <u>a bluer</u> shade of purple than Purple #1.
5 0
3 years ago
Read 2 more answers
The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypote
EastWind [94]
The hypotenuse length is √(4*4 + 3*3) = 5 (not √7 I suppose)
The area is base*half height = 4*3/2 = 6.

In short, I don't think complex numbers really interfere here.

4 0
3 years ago
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