Question

A family has three children. Assuming a boy is as likely as a girl to have been born, what are the following probabilities? Two are girls and one is a boy. Incorrect: Your answer is incorrect. At least 1 is a boy. Incorrect: Your answer is incorrect.

Answer 1

Answer:

3/8 , 3/8

Step-by-step explanation:

Assumption: A boy is as likely as a girl

hence P(B)= P(G)= 1/2= 0.5

family has 3 children

find the probability of

A) two girls and a boy.

it can happen in following way

BGG, GGB or GBG

P(BGG)= P(GGB)= P(GBG) = $\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}$

= 1/8

therefore , probability of two girl and a boy= $\frac{1}{8} +\frac{1}{8} +\frac{1}{8}$ = 3/8

B) At least One boy

it can happen is in

BGG, BBG, BBB

P(BGG)= P(BBG)= P(BBB) = $\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}$

= 1/8

therefore , probability of at least one boy= $\frac{1}{8} +\frac{1}{8} +\frac{1}{8}$ = 3/8