Answer:
1/3 - 1/4 = 1/12.
Step-by-step explanation:
Answer:
i think it is the first one that is correct
i hope this helped
Step-by-step explanation:
Answer:

Step-by-step explanation:
<u><em>Given equation is</em></u>

Adding 42 to both sides

Completing squares

Adding (3)² => 9 and (3)² => 9 to both sides

Comparing it with
where Center = (h,k) and Radius = r
We get:
Center = (3,3)
Radius = 
9514 1404 393
Answer:
D) 45 and 1.2
Step-by-step explanation:
The "varies inversely" relationship is described by the equation ...
y = k/x . . . . . . y varies inversely with x (and vice versa)
The value of k can be found from known values of x and y:
xy = k . . . . . . multiply the above equation by x
(10)(6) = k = 60 . . . . using the given values
__
To check if a given pair of numbers satisfies ...
y = 60/x
you can multiply them together to see if the product is 60.
(A) 12×5 = 60
(B) 15×4 = 60
(C) 25×2.4 = 60
(D) 45×1.2 = 54 . . . . . not a possible pair of corresponding values.
45 and 1.2 are not a possible solution for x and y.
Answer:
x=3
Step-by-step explanation:
Given,
1 = 1/(x-2)
Multiply both sides by (x-2),
1*(x-2) = 1/(x-2) * (x-2)
x-2 = 1
Adding 2 on both sides,
x-2+2 = 1+2
x = 3