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xenn [34]
3 years ago
15

What is 55 divided by 1 1/2

Mathematics
2 answers:
svetoff [14.1K]3 years ago
6 0
Answer: 55/2

1. Any expression divided by remains the same
55 1/2

2. Calculate the product
55/2
Karolina [17]3 years ago
5 0

Answer:

55 divided by 11/2 is 10

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Please help.. What is the surface area of the rectangular prism below?
In-s [12.5K]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A die is rolled 6 times. Find the probability P(of exactly 4 occurrences of 2).
Alex

the amount of times the die is rolled is equal to 100%

if 2 was to be rolled 4 out of 6 times that would mean it would be 80%

the answer is D.

6 0
4 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.7
Zinaida [17]

Answer:

(a) The probability that the sample average sediment density is at most 3.00 is 0.092.

    The probability that the sample average sediment density is between 2.70 and 3.00 is 0.477.

(b) The sample size must be at least 77.

Step-by-step explanation:

The random variable <em>X</em> ca be defined as the sediment density (g/cm) of a specimen from a certain region.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 2.7 and standard deviation, <em>σ</em> = 0.75.

(a)

A random sample of <em>n</em> = 25 specimens is selected.

Compute the probability that the sample average sediment density is at most 3.00 as follows:

Apply continuity correction:

P(\bar X\leq 3.00)=P(\bar X

                    =P(\bar X

                    =P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}

                    =P(Z

Thus, the probability that the sample average sediment density is at most 3.00 is 0.092.

Compute the probability that the sample average sediment density is between 2.70 and 3.00 as follows:

P(2.70

                                =P(0

*Use a <em>z</em>-table.

Thus, the probability that the sample average sediment density is between 2.70 and 3.00 is 0.477.

(b)

It is provided that:

P(\bar X\leq 3.00)\geq 0.99

P(\bar X

P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}

P(Z

The value of <em>z</em> for the probability above is

<em>z</em> ≥ 2.33

Compute the value of <em>n</em> as follows:

\frac{|2.50-2.70|}{0.75/\sqrt{n}}\geq 2.33

\frac{|-0.20|}{2.33}\geq \frac{0.75}{\sqrt{n}}

\sqrt{n}\geq \frac{0.75\times 2.33}{|-0.20|}\\\sqrt{n}\geq 8.7375\\n\geq 76.3439\\\approx n\geq 77

Thus, the sample size must be at least 77.

8 0
3 years ago
The length of the small leg of a 30 -60 -90 degree triangle is 5. What is the perimeter of the triangle?
vivado [14]

Answer:

option (B)

15 + 5√3

Step-by-step explanation:

In a 30-60-90 triangle, you can find the measure of any of the three sides, simply by knowing the measure of at least one side in the triangle.

Given in the question,

length of small leg = 5

As we know that

The hypotenuse is equal to twice the length of the shorter leg

<h3>hypotenuse = 2(5) =10</h3>

The longer leg is equal to multiplying the shorter leg by the square root of 3

<h3>other leg = 5√3</h3>

Perimeter of a triangle = sum of the length of three sides

                                     =  5√3 + 10 + 5

                                     = 15 + 5√3

3 0
4 years ago
Need help on this!! 10 points!!
Reptile [31]

Answer:

Step-by-step explanation:

The change of base formula is

log_a(b)=\frac{log_{10}b}{log_{10}a} so filling in our given:

log_{13}}(297)=\frac{log_{10}297}{log_{10}13} (Note: you do not have to put the base of 10 in the change of base formula because the "normal" base for a log is 10 and that is how your calculator figures it.)

Do this on your calculator to get

\frac{log297}{log13}=2.2198 Not sure how many decimal places you needed!

7 0
3 years ago
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