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sesenic [268]
3 years ago
5

A magnifying glass is a concave/convex lens that forms a virtual/real image.

Physics
1 answer:
romanna [79]3 years ago
8 0

Answer:

Convex and Virtual

Explanation:

A concave lens makes things appear smaller while a convex can make it magnified while being virtual. It appears right side up which makes it virtual.

Hope you do a good job!!  :)

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What is the magnitude of a point charge in coulombs whose electric field 58 cm away has the magnitude 2.8 N/C?
Yuliya22 [10]

Answer:

q = 1.05 × 10^-10 C

Explanation:

E = 2.8 N/C

r = 58cm = 0.58m

k = 9×10^9

q = ?

E = f/q

E = kq/r²

q = E*r²/k

q = (2.8×0.58²)÷9×10^9

q = 1.05 × 10^-10 C

8 0
3 years ago
Convert the unit of 0.00023 kilograms into grams. (Answer in scientific notation)
Rus_ich [418]

Answer:

2.3  ×  10^{-1}  

Explanation:

1 kg = 1000 g.

0.00023 kg x 1000 g = 0.23 grams

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3 years ago
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A ball with a mass of 0.5 kg is hit with a force of 2.5 N what is its acceleration?
stealth61 [152]

Explanation:

50 m/s may squared siya sa dun sa may s

8 0
4 years ago
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The image shows the path of a ball that’s thrown. At positions and , kinetic energy is maximum. At position , potential energy i
zimovet [89]

Answer:

there is no image

Explanation:

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3 years ago
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Divers change their body position in midair while rotating about their center of mass. In one dive, the diver leaves the board w
OlgaM077 [116]

Answer:

Her angular velocity when tucked is greater than when straight by a factor of 0.23

Explanation:

Moment of inertia (I) = mr^2 = mv^2/w^2

m is mass of the diver

v is diver's linear velocity

w is her angular velocity

When straight, I = 14 kg.m^2

mv^2/w^2 = 14

w^2 = mv^2/14

w = sqrt(mv^2/14) = 0.27sqrt(mv^2)

When tucked, I = 4 kg.m^2

w^2 = mv^2/4

w = sqrt(mv^2/4) = 0.5sqrt(mv^2)

Her angular velocity when tucked is greater than when straight by 0.23 (0.5 - 0.27 = 0.23)

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4 years ago
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