<u>Solution and Explanation:</u>
The following calculation is made in order to find out the area and the final velocity vector.
Using the given information and the data in the question,
m1u1 + m2u2 = (m1 + m2) multiply with v
40000 multiply with ( -20i ) + 60000 multiply with ( 10j ) = 100000 multiply with v
Therefore, v = -8i + 6j
That is |v| = 10 knots towards the 36.86 degree north of the west
Answer:
Protons have about the same mass as electrons is false
Explanation:
Electrons and protons have the same magnitude on charge but opposite sign
: charge of electron
: charge of proton
Neutrons have no charge.
An atom is composed of protons and neutrons in the nucleus and electrons surrounding it, so a neutral atom has the same number of protons and electrons to has a net charge of zero. So, all the facts mentioned are true.
The false one is that protons have about the same mass as electrons, because the mass of an electron is
and the mass of a proton is
so the mass of a proton is a lot of bigger than electron mass.
Answer:
D. 10 T
Explanation:
When a particle is moving in a magnetic field, the magnetic force provides the centripetal force that keeps the particle in circular motion.
The cyclotron period (the period the particle takes to complete one orbit) can be found to be

where
m is the mass of the particle
q is its charge
B is the magnetic field
As we see, the period is directly proportional to the mass of the particle.
In this problem, the second particle is ten times as massive as the first one:
m' = 10 m
while the speed is the same. So, the period of the second particle is

Answer:
energy can move from one location to another, the particles of matter in the medium return to their fixed position. A wave transports its energy without transporting matter.
Answer:
c. No. An equation may have consistent units but still be numerically invaid.
Explanation:
For an equation to be corrected, it should have consistent units and also be numerically correct.
Most equation are of the form;
(Actual quantity) = (dimensionless constant) × (dimensionally correct quantity)
From the above, without the dimensionless constant the equation would be numerically wrong.
For example; Kinetic energy equation.
KE = 0.5(mv^2)
Without the dimensionless constant '0.5' the equation would be dimensionally correct but numerically wrong.