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3 years ago

Which law describes the interactions between charged particles when they are not in contact?

Physics

2 answers:

natulia [17]3 years ago

7 0

The answer would be the coulombs law.

mojhsa [17]3 years ago

7 0

Answer:

B) Coulomb's law

Explanation:

As per coulombs law if two point charges are placed at some distance from each other then the force of interaction between them is given as

$F = \frac{kq_1q_2}{r^2}$

here we know that

$q_1 , q_2$ = two charges between which force of interaction is required

d = distance between two charges

$k = \frac{1}{4\pi \epsilon_0}$

Faraday law is used to find the induced EMF due to changing magnetic flux

Ohm's law is used to relate potential difference between the ends of a conductor with its resistance and its current

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The sound from a single source can reach point O by two different paths. One path is 20.0 m long and the second path is 21.0 m l

aleksandrvk [35]

Answer:

minimum frequency = 170 Hz

Explanation:

given data

One path long = 20 m

second path long = 21 m

speed of sound = 340 m/s

solution

we get here destructive phase that is path difference of minimum $\frac{\lambda}{2}$

here λ is the wavelength of the wave

so path difference will be

21 - 20 = $\frac{\lambda}{2}$

λ = 2 m

and

velocity that is express as

velocity = frequency × wavelength .............1

frequency = $\frac{340}{2}$

minimum frequency = 170 Hz

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4 years ago

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Maksim231197 [3]

Answer:

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3 0

3 years ago

In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these s

riadik2000 [5.3K]

Answer:

Part a)

$\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}$

Part b)

$\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}$

Explanation:

As we know that the see saw bar is massless so here torque due to two masses is given as

$\tau = I\alpha$

here we will have

$\tau = (m_1g - m_2g)(\frac{L}{2})$

now we will have inertia of two masses given as

$I = (m_1 + m_2)(\frac{L}{2})^2$

now we have

$I = (m_1 + m_2)\frac{L^2}{4}$

now the angular acceleration is given as

$\alpha = \frac{\tau}{I}$

so we have

$\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}$

Part b)

Now if the rod is not massles then we will have total inertia given as

$I = (m_1 + m_2)(\frac{L}{2})^2 + \frac{m_{bar}L^2}{12}$

so we will have

$I = (m_1 + m_2)\frac{L^2}{4} + \frac{m_{bar}L^2}{12}$

now the acceleration is given as

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}$

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4 years ago

Stick a fork into each end of the root vegetable as shown. The forks should be on the same side of the vegetable, and

zhuklara [117]

Answer:

Yes

Explanation:

There is a position that works better than this and that is switching the sides of the forks.

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3 years ago

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melisa1 [442]

Answer:

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Explanation:

hope it helps ya

5 0

3 years ago