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Illusion [34]
3 years ago
14

Plzzz help me fast i have absolutly no f-r-i-c-k-e-n idea what this is or how to do it

Physics
2 answers:
Masja [62]3 years ago
8 0

Answer:

Explanation:

PE=mgh

mass, m is 50kg

gravity, g is 10m/s^2

height, h is 4m

So Potential Energy, PE

=50*10*4

=2000J

vodomira [7]3 years ago
4 0

P.E =mgh

=5o x 4 x 10

Explanation:

= 2000J

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I need help with this please
kondaur [170]

Answer:

1. The respiratory system functions when our involuntary nervous system sends impulses to the muscles in the diaphragm; thereby, causing the lungs to expand and contract.

2. The respiratory system oxygenates the blood which is vital for bodily function as oxygenated blood is carried from your lungs to the left side of your heart, to be circulated throughout the body. Furthermore deoxygenated blood is carried back to the right side of your heart to get oxygenated once more.

3. The other body systems that are crucial for the lungs to function are the nervous system and the muscular system.

4. without the raspatory system the body wouldn't receive any oxygen and the brain would slowly die. therefore, without the brain the heart would stop functioning and atrophy etc.

Explanation:

6 0
3 years ago
If a an object is traveling at a rate of 5 meters per second squared with a force of 10 Newtons, what is the mass of the object?
Svetllana [295]

Answer:

2 kg

Explanation:

Acceleration = 5 m/s^2

Force = 10 N

Force = mass * acceleration

mass = force / acceleration

mass = 10 / 5

mass = 2 kg

8 0
3 years ago
Calculate the molecular weight of Aluminium hydroxide​
Vedmedyk [2.9K]

Al(OH)3 = 26.98 + [(16×3) + (1.01×3)] = 26.98 + 51.03 = 78.01 and the unit will be g/mol

<h3><em>Al(OH)3 = 78.01 g/mol</em></h3>
5 0
3 years ago
A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can
Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

\mu is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

v=85 mph \cdot \frac{1609}{3600}=38.0 m/s is the speed

And solving for \mu, we find the coefficient of friction required to keep the car in circular motion:

\mu = \frac{v^2}{rg}=\frac{38.0^2}{(750)(9.8)}=0.196

Learn more about circular motion:

brainly.com/question/2562955  

brainly.com/question/6372960  

#LearnwithBrainly

8 0
3 years ago
What is it that if you have, you want to share me, and if you share, you do not have?
Colt1911 [192]

Answer:

Secrets? Cuz if I share you the secrets then the secrets will no longer will be secrets.

4 0
3 years ago
Read 2 more answers
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