5/8=0.625 4/5=.8
5/8 because 5/8=0.625 and because its 2x you multiply 0.625 by 2=1.25 then you do 1.25+5=6.25 4/5=.8 6.25 times .8=5 5-4=1
X=5/8 or 0.625
We have that you can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
From the question we are told
If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A
Generally the equation for the Concentration Volume relationship is mathematically given as

Therefore
You can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
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