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sattari [20]
3 years ago
13

The periodic table

Chemistry
2 answers:
astra-53 [7]3 years ago
5 0

it's Lithium or Li

..............................

SVETLANKA909090 [29]3 years ago
3 0

Answer:

El litio encabeza la familia de los metales alcalinos en la tabla periódica. En la naturaleza se encuentra como una mezcla de los isótopos Li6 y Li7. Es el metal sólido más ligero, es blando, de bajo punto de fusión y reactivo.

Explanation:

You might be interested in
Suppose a new liquid were discovered that is identical to water in every way except that it has a lower latent heat of fusion. W
faltersainse [42]

Answer:

It would take less time, because having a lower temperature of latent heat means that at a lower temperature it merges, therefore the closer it will be to the temperature of solification which is 0 degrees Celsius or Celsius ... It is then that it would solidify in less time than water

Explanation:

By acting and having all the same properties as water except for latent heat, it considers that the solidification temperature is 0 degrees Celsius like water.

3 0
3 years ago
Read 2 more answers
2Al + 3H2SO4 -> Al2(SO4)3 + 3H2How many grams of aluminum sulfate would be formed if 250g H2SO4 completely reacted with alumi
bazaltina [42]

Answer:

290.82g

Explanation:

The equation for the reaction is given below:

2Al + 3H2SO4 -> Al2(SO4)3 + 3H2 now, let us obtain the masses of H2SO4 and Al2(SO4)3 from the balanced equation. This is illustrated below:

Molar Mass of H2SO4 = (2x1) + 32 + (16x4) = 2 + 32 +64 = 98g/mol

Mass of H2SO4 from the balanced equation = 3 x 98 = 294g

Molar Mass of Al2(SO4)3 = (2x27) + 3[32 + (16x4)]

= 54 + 3[32 + 64]

= 54 + 3[96] = 54 + 288 = 342g

Now, we can obtain the mass of aluminium sulphate formed by doing the following:

From the equation above:

294g of H2SO4 produced 342g of Al2(SO4)3.

Therefore, 250g of H2SO4 will produce = (250 x 342)/294 = 290.82g of Al(SO4)3

Therefore, 290.82g of aluminium sulphate (Al(SO4)3) is formed.

7 0
3 years ago
The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

7 0
3 years ago
When the temperature in a room increases from 25°C to 33°C, changes from a solid to a liquid.
mr Goodwill [35]

Answer:

true

Explanation:

Because ice melts if the temperature increasese

8 0
3 years ago
Caleb has a 860-kilogram car sitting in his back yard, gathering rust.
emmasim [6.3K]
<h3>Answer:</h3>

A. 860 kg

<h3>Explanation:</h3>

To answer the question we need to understand that;

  • Mass refers to the amount of matter in an object.
  • Weight, on the other hand, refers to the gravitational pull of an object to a given surface.
  • Mass is measured using a spring balance.

We also need to know that;

  • The mass of an object remains constant every where irrespective of the gravitational acceleration.
  • Therefore, an object on the surface of the earth would have the same mass as on the surface of the moon.
  • In this case; the mass of the car remains the same on the outer space as on the back yard.
3 0
3 years ago
Read 2 more answers
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