35 g (Rounded to the nearest tenth) H₂O can be made when 5.8 moles of HNO₃ are consumed.
<h3>What is Mole ratio ?</h3>
Mole Ratio is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation.
The mole ratio is therefore used to convert between quantities of compounds in a chemical reaction.
The mole ratio of HNO₃ and H₂O is 6 : 2
Hence, 16.9 moles of HNO₃ will produce = 2/6 × 5.8 = 1.93 moles of H₂O
Also,
Mass = Moles × M.Mass
Mass = 1.93 mol × 18.02 g/mol
Mass = 34.83 g H₂O
= 35 g (Rounded to the nearest tenth)
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Answer:
Definition of Inert. An inert chemical is one that is stable and unreactive under specified conditions. ... However, most of the noble gases have now been observed to form compounds, although generally under unusual conditions. Helium and neon are highly inert; they form no compounds.
Answer:
Manganese dioxide is a catalyst.
Explanation:
The decomposition of hydrogen peroxide into water and oxygen is a slow reaction and MnO₂ is used as a catalyst to speed up the reaction.
The role of MnO₂ (catalyst):
- Chemical reactions occur faster in the presence of a catalyst because the catalyst provides an alternative reaction pathway with a lower activation energy than the non-catalyzed mechanism.
- In catalyzed mechanisms, the catalyst usually reacts to form a temporary intermediate, which then regenerates the original catalyst in a cyclic process.
- A substance which provides a mechanism with a higher activation energy does not decrease the rate because the reaction can still occur by the non-catalyzed route.
- The catalyst does not used up in the reaction.
So, the right choice is:
Manganese dioxide is a catalyst.
In my opinion, the correct answer among the choices above is option B. AN atom having four electrons in its valence shell is capable of single, double, or triple covalent bonds. This is because 4 electrons of the atom can be shared with other atoms.
Given the amount of sample: 24.25 mL;
the concentration of the titrant (NaOH) = 0.1010 mol / L NaOH
the amount of the titrant used for titration = 14.83 mL
The concentration of a solution of lactic acid is determined by:
C(lactic acid in the sample) = ((0.1010 mol / L) * (14.83mL/1000) / (24.25mL/1000)
C = 0.0618 mol