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Svetllana [295]
3 years ago
5

Randy is deciding which cell phone plan is the best deal for him to buy. Super Cell charges a monthly fee of $15 and also charge

s $0.05 per call. Which equation represents the cost of service at Super Cell? (Use M as the monthly charge, in dollars, and C as the number of calls placed.)
A
M = .05 + 15C

B
M = .05C + 15

C
M = .05 + C + 15

D
M = .05C x 15
Mathematics
1 answer:
svp [43]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Add the monthly fee $15 and the amount of times he called.

$15 + 0.05C = M

Hoped it helped you

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Which product is positive?
Natalija [7]

Option D:

\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right) is positive product.

Solution:

<em>If the negative sign is in even number of times then the product is positive.</em>

<em>If the negative sign is in odd number of times then the product is negative.</em>

To find which product is positive:

Option A:

$\left(\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(-\frac{1}{3}\right)\left(-\frac{2}{7}\right)

Here, number of negative signs = 3

3 is an odd number.

So, the product is negative.

Option B:

$\left(-\frac{2}{5}\right)\left(\frac{8}{9}\right)\left(-\frac{1}{3}\right)\left(-\frac{2}{7}\right)

Here, number of negative signs = 3

3 is an odd number.

So, the product is negative.

Option C:

$\left(\frac{2}{5}\right)\left(\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(-\frac{2}{7}\right)

Here, number of negative sign = 1

1 is an odd number.

So, the product is negative.

Option D:

$\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right)

Here, number of negative sign = 2

2 is an odd number.

So, the product is positive.

Hence option D is the correct answer.

\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right) is positive product.

4 0
3 years ago
Need help asap need to get this done​
djyliett [7]

Answer:

3:4

Step-by-step explanation:

8/6=4/3

12/9=4/3

16/12=4/3

5 0
2 years ago
Determine whether the normal sampling distribution can be used. The claim is p &lt; 0.015 and the sample size is n
Svetradugi [14.3K]

Complete Question

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150

Answer:

Normal sampling distribution can not be used

Step-by-step explanation:

From the question we are told that

    The  null hypothesis is  H_o  :  p =  0.015

     The  alternative hypothesis is    H_a  :  p  <  0.015

     

The  sample size is  n= 150

Generally in order to use  normal sampling distribution  

     The value  np  \ge  5

So  

         np =  0.015 * 150

         np =  2.25

Given that  np < 5   normal sampling distribution  can not be used

8 0
3 years ago
Plzz help me im going to most more like this because im not understanding it
lisov135 [29]
Hi there!

In order to solve, you can use substitution. This means that you use one equation and solve for one variable, then use that one equation and plug it into the other equation. Here's how we'd do it:

WORK:
x = 12 - y (since x is already solved for, we'll use that to plug into the other given equation.
2(12 - y) + 3y = 29 (using substitution)
24 - 2y + 3y = 29
24 + y = 29
y = 5
Plug the value of y back into the first equation
x = 12 - 5
x = 7

ANSWER:
A - x = 7, y = 5

It seems as though you're having some trouble with these questions, PLEASE MESSAGE ME!! I'd be more than happy to help you work through as many problems as you need until you get the hang of it (plus, it doesn't cost you any points!)

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
5 0
3 years ago
How many ways can a group of three boys and three girls be seated in a row of six seats if boys and girls must alternate in the​
IgorC [24]

Answer:

24

Step-by-step explanation:

there are 6 seats and 3 boys, 3 girls.

First seat can be given to either boy or a girl.

So there are two ways.

If a boy is selected say, then he has to occupy 3rd and 5th only.

There are 2 ways

Now available positions are 2nd, 4th and 6th, in this girls can be arranged in 3! ways = 6

So total number of ways =

2x2x6 = 24

8 0
3 years ago
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