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faltersainse [42]
3 years ago
12

Divers looking for a sunken ship have defined the search area as a triangle with adjacent sides of length 2.75 miles and 1.32 mi

les. the angle between the sides of the triangle is 35. to the nearest hundreth, find the search area
a. 2.08 mi^2
b. 2.97 mi^2
c. 1.49 mi^2
d. 1.04 mi^2
Mathematics
1 answer:
butalik [34]3 years ago
3 0
When you know one side, the included angle and the other side you can use this triangle area formula:
<span>Area = ½ • side 1 • sine (A) • side 2
Area = .5*2.75*sine(35)*1.32
</span>Area = <span>.5*2.75*0.57358*1.32
</span><span><span><span>Area = 1.0410477 square miles
 </span></span></span>




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Answer:The expressions for the payment made to Mary are,

        (Monday)      90 = 15m + b

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where m and b are the fee per student and the base fee, respectively. Solving for m and b, the values are 4 and 30.

The equation that represents Mary's earning is

                                   y = 4x + 30

For 20 students,

                                   y = 4(20) + 30 = 110

For Lisa's earnings,

                                    y = 8x + 15

Substituting 20,

                                   y  =8(20) + 15 = 175

Thus, Lisa would earn more than Mary by $65.

Read more on Brainly.com - brainly.com/question/1560980#readmore

Step-by-step explanation:

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Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 72, \sigma = 10

The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.

X = 82:

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 72}{10}

Z = 1

Z = 1 has a p-value of 0.84.

X = 72:

Z = \frac{X - \mu}{\sigma}

Z = \frac{72 - 72}{10}

Z = 0

Z = 0 has a p-value of 0.5.

0.84 - 0.5 = 0.34.

Out of 200 students, the number is given by:

0.34 x 200 = 68 students with scores between 72 and 82.

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