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bearhunter [10]
3 years ago
5

a circle with radius 3 has a sector with a central angle of 17/9 pi radians. what is the area of the sector?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

The area of the sector is 26.69

Step-by-step explanation:

First of all we need to calculate the area

To solve this problem we need to use the area formula of a circle:

a = area

r = radius =   3

π = 3.14

a = π * r²

we replace with the known values

a =  3.14 *  (3)²

a =  3.14 * 9

a = 28.26

The area of the circle is 28.26

A complete circle has 2pi radians

We divide 17/9 pi by 2pi and obtain the fraction of the total circle

(17pi/9) / 2pi = 17/18

we multiply this fraction with the area of the circle and obtain the area of the sector

28.26  * 17/18 = 12.43cm

The area of the sector is 26.69

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Use the distance formula to find the distance between two points.

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There are 1,826 days in 5 yr. In relation to the leap year, there are 1826.25 days in 5 yrs. That is because there are really 365.25 days in a year (making every four years a leap year). So, when you multiply 365.25 by 5, you get 1826.25. 
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A sector from a radius 4 circle has an area of 8 square feet. Find the perimeter of the sector. Use an exact answer.
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8 0
3 years ago
The length of each edge of a cube is decreased by 40 percent By what percent does the volume of the cube decrease? Express your
lora16 [44]

Answer:

78% (to the nearest tenth)

Step-by-step explanation:

Volume of a cube = (length )³

Let the length of the cube = y

Original volume = y³

if the length is decreased by 40%, then new length = 1- (40% of y)

                                                                                     = 1-0.4y

                                                                                     =  0.6%

New volume (after decreasing the length) = (0.6y)³

                                                                      =  0.216‬‬y³

% Volume decrease = (Original volume - New volume)/Original Volume x 100%

                                 =  (y³ - 0.216‬‬y³)/ y³  x 100%

                                 = 0.784y³/y³  x 100%

                                 =78.4%

                                ≈78%

5 0
3 years ago
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What is the midpoint of QR. Q(2,4) and R(-3,9)
Eduardwww [97]

Answer:

The answer is

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

Q(2,4) and R(-3,9)

The midpoint is

M = ( \frac{2 - 3}{2}  \:  , \:  \frac{9 + 4}{2} ) \\

We have the final answer as

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Hope this helps you

6 0
3 years ago
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