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AlexFokin [52]
3 years ago
15

The equation 7x - 10y = 30 is written in standard form. What is the first step when writing an equivalent equation which solves

for y?
Mathematics
1 answer:
kotykmax [81]3 years ago
5 0
Add 30 to both sides
You might be interested in
How much is 5a(6b+12)
andreev551 [17]
When writing an expression in expanded form, we just need to multiply what's outside the parentheses by everything that is inside the parentheses.

5a (6b + 12)

(5a * 6b) + (5a * 12)

30ab + 60a

And that is our answer.
5a (6b + 12) in expanded form is 30ab + 60a.
Hope that helped =)
6 0
3 years ago
Read 2 more answers
please help me with this! this was due yesterday and i need to get it done but im stuck on this question
Paul [167]

Answer:

60* and 30*

Step-by-step explanation:

If two angles are complementary then they will add up to be 90, or inversely, if two angles add up to be 90, then they are complementary. If you know one acute angle, you can calculate its complementary angle by subtracting 90 and the angle.

5 0
3 years ago
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if the vertex of a parabola is (-4,6) and another point on the curve is (-3,14), what is the coefficient of the squared expressi
Softa [21]

Answer:

8

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, 6 ), thus

y = a(x + 4)² + 6

To find a substitute (- 3, 14) into the equation

14 = a(- 3 + 4)² + 6 ( subtract 6 from both sides )

8 = a

Thus the coefficient of the x² term is a = 8

3 0
3 years ago
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
Write 6 17/20 as a decimal
djverab [1.8K]

Answer:

6.85

Step-by-step explanation:

6 17/20

Convert to improper fraction.

137/20

Divide.

= 6.85

3 0
3 years ago
Read 2 more answers
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