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3 years ago

A race walker completed 913 mile walk in 2.5 hrs. What is the walkers speed? Please show work

1 answer:

4 0

The walker's speed is

(913 miles) / (2.5 hours) = 365.2 miles per hour

(Hey, I just solve um. I don't get into the philosophy.)

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Find the unit rate. Round to the nearest hundredth, If necessary. $290 for 12ft

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Answer:

24.17

Step-by-step explanation:

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3 years ago

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NEED HELP ASAP!!!!!

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D. Because 5 and 5 could land on any

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Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago

And I oop- T^T Send help

Rufina [12.5K]

I sent help but no one answered :(

Jk, I got you fam

12(t + 2) + 4 ≥ - 8

12t + 24 + 4 ≥ - 8

12t + 28 ≥ - 8

12t ≥ - 8 - 28

12t ≥ - 36

t ≥ - 36 ÷ 12

t ≥ - 3

Solution:

t ≥ -3

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3 years ago

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DOES ANYONE KNOW HOW TO DO THIS???

Anna11 [10]

Answer:

Cost of a pound of chocolate chips: $3.5

Cost of a pound of walnuts: $1.25

Step-by-step explanation:

x - cost of a pound of chocolate chips

y - cost of a pound of walnuts

We create two equations based on the information we have:

3x+2y=13

8x+4y=33

The whole point of these problems os to get rid of x or y. In this question, we can do this by multiplying both sides of the first equation by 2, and then subtracting it from the second equation:

8x+4y=33

6x+4y=26

2x=7

x=3.5

Then we change x for 3.5 in the first equation:

3×3.5+2y=13

10.5+2y=13

2y=2.5

y=1.25

Hope this helps!

4 0

3 years ago