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Gre4nikov [31]
3 years ago
11

The deflection of alpha particles in rutherford’s gold foil experiments resulted in what change to the atomic model? the additio

n of energy levels and orbitals to the electron cloud the addition of a small, dense nucleus to the center of the atom the addition of wave properties to the characteristics of an electron the addition of neutrons to the nucleus of the atom
Physics
2 answers:
skelet666 [1.2K]3 years ago
5 0
The answer is: The addition of a small dense nucleus at the center of the atom.
pogonyaev3 years ago
4 0

Answer:

Addition of a small, dense nucleus to the center of the atom

Explanation:

Most alpha particles were observed to pass straight through the gold foil, which implied that atoms are composed of large amounts of open space. Some alpha particles were deflected slightly, suggesting interactions with other positively charged particles within the atom.

Still other alpha particles were scattered at large angles, while a very few even bounced back toward the source. Only a positively charged and relatively heavy target particle, such as the proposed nucleus, could account for such strong repulsion.

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The heat pump is designed to move heat. This is only possible if certain relationships between the heats and temperatures at the
Pie

Answer:

There are no answer chooses to this question

Explanation:

7 0
3 years ago
Un vehicle surt, en un instant, d'un punt A cap a un altre punt B amb una velocitat constant de 36 km/h. Després d'un minut(60 s
kati45 [8]



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6 0
3 years ago
What is the period of a simple pendulum 47 cm long (a) on the Earth, and ( b) when it is in a freely falling elevator?
Liula [17]

Answer:

a)1.37 s

b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm              ( 1 m =100 cm)

L= 0.47 m

a)

On the earth :

Acceleration due to gravity = g

We know that time period of the simple pendulum given as

T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}

Here

g_{eff}= g

Now by putting the values

T=2\pi \times\sqrt{ \dfrac{0.47}{9.81}}

T=1.37 s

b)

Free falling elevator :

When elevator is falling freely then

g_{eff}= 0            ( This is case of weightless motion)

Therefore

T=2\pi\sqrt{ \dfrac{L}{0}

T=∞  (Infinite)

6 0
3 years ago
A duck with a mass of 0.90 kilograms flies at a rate of 12.0 m/s. What is the kinetic energy of the duck?
bija089 [108]
It should be at about 65J. Not sure, hope I helped.
6 0
3 years ago
Read 2 more answers
An iron railroad rail is 700 ft long when the temperature is 30°C. What is its length when the temperature is – 10°C?
MAVERICK [17]

Answer:

699.67ft

Explanation:

We are given with,

  • α = 1.2×10⁻⁵ / °C
  • L₀ = 700 ft
  • ΔT = -10°C − 30°C = -40°C

Now, We have to find ΔL:

  • ΔL = (1.2×10⁻⁵ / °C) (700 ft) (-40°C)
  • ΔL = −0.336

Rounded to two significant figures, the change in length is −0.33ft.

<u>Therefore, the final length is approximately 700 ft − 0.33 ft = 699.67ft</u>.

6 0
3 years ago
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