Answer:
55.80 g/s
Explanation:
From the question,
Flow rate = density×Area×velocity.
φ = ρ×A×V................... Equation 1
Where φ = flow rate of blood, ρ = density of blood, A = cross sectional area of blood, V = velocity of blood.
Given: ρ = 0.846 g/cm³, A = 1.36 cm², V = 48.5 cm/s.
Substitute these values into equation 1
φ = 0.846×1.36×48.5
φ = 55.80 g/s
Hence, the flow rate of the blood = 55.80 g/s
Answer:
-2.63 Joules
2.63 Joules
Explanation:
= Initial compression = 5.89 cm
= Final compression = -15.4 cm
k = Spring constant = 260 Nm
Work done by a spring is given by
Work done by the spring is -2.63 Joules.
Change in kinetic energy is given by
Here, it is assumed that change in kinetic energy is zero as velocity and amlitude are not mentioned.
So,
The work done by the applied force is 2.63 Joules.
At a point on the streamline, Bernoulli's equation is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = density of air, 0.075 lb/ft³ (standard conditions)
g = 32 ft/s²
Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s
Point 2 (stagnation):
At the stagnation point, the velocity is zero.
The density remains constant.
Let p₂ = pressure at the stagnation point.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
= 314.37 lb/ft²
= 314.37/144 = 2.18 lb/in²
Answer: 2.2 psi
11,000 m = 11 km
11 km/s over 380,000km
380,000 / 11 = 34545.4 seconds
34545.4 / 60 = 575.7 minutes
Answer:
option a
Explanation:
a- All matter is composed of small particles.
