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svp [43]
3 years ago
13

Radioactive elements decay at a know rate known as half-life. Choose all of the correct statements concerning half-life. Carbon-

14 has a half-life of 5,730 years. A 30 gram sample will be 10 grams after 5,730 years. Nickel-59 has a half-life of 76,000 years. A sample would go through 3 half-lives in 228,000 years. Hafnium-182 has a half-life of 9 million years. A 38 gram sample would be 4.75 grams in 27 million years. Iron-60 has a half-life of 1.5 million years. In 6 million years a 40 gram sample would be reduced to 10 grams. Lead-202 has a half-life of 52,500 years. The original sample must have been 120 grams if you have a 60 gram sample after 105,000 years.
Chemistry
2 answers:
Lera25 [3.4K]3 years ago
8 0

Answer:

-Nickel-59 has a half-life of 76,000 years. A sample would go through 3 half-lives in 228,000 years.

-Hafnium-182 has a half-life of 9 million years. A 38 gram sample would be 4.75 grams in 27 million years.

Explanation:

9966 [12]3 years ago
6 0

Explanation:

Half life is simply the amount of time it takes for half of a substance to decompose.

Options;

- Carbon-14 has a half-life of 5,730 years. A 30 gram sample will be 10 grams after 5,730 years. This is incorrect. After 5730 years, 15g of the sample ought to remain.

- Nickel-59 has a half-life of 76,000 years. A sample would go through 3 half-lives in 228,000 years. This is correct. 3 * 76000 = 228,000

- Hafnium-182 has a half-life of 9 million years. A 38 gram sample would be 4.75 grams in 27 million years. This is incorrect. Mass after 3 half lives (27/9) = 9.5 (38 / 2 / 2)

- Iron-60 has a half-life of 1.5 million years. In 6 million years a 40 gram sample would be reduced to 10 grams. This is incorrect. Mass after 4 half lives (6 / 1.5) = 2.5 gram (40 / 2 / 2 /2 / 2)

- Lead-202 has a half-life of 52,500 years. The original sample must have been 120 grams if you have a 60 gram sample after 105,000 years. This is incorrect. Original sampe = 240 gram. So after 2 half lives (105,000/52500), mass left = 60 (240 / 2 /2)

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In test tube 3, 3 mL of .002 M Fe(III) solution is combined with 7 mL of .02 M 5-sulfosaliclic acid (SSA) solution. What is the
Nutka1998 [239]

Answer:

0.96

Explanation:

Number of moles of Fe(III) = 3/1000 *  0.002 M = 6 * 10^-6 moles

Number of moles of SSA = 7/1000 * 0.02 = 1.4 * 10^-4 moles

Total number of moles =  6 * 10^-6 moles +  1.4 * 10^-4 moles

Mole fraction of SSA = number of moles of SSA/ total number of moles.

Mole fraction of SSA =  1.4 * 10^-4 moles/  6 * 10^-6 moles +  1.4 * 10^-4 moles

Mole fraction of SSA = 0.96

8 0
3 years ago
At the energy-generating station, the coal is burned. Burning
OverLord2011 [107]

Answer:

The correct answer is - false.

Explanation:

At the energy-generating station, when the coal is burned, the chemical energy store in the coal converted into thermal energy and light or luminous energy.

The thermic energy generated used to heat and boil the water or liquid to generate the gas and generate the kinetic energy to move the fan that is desgined to generate the electrical energy.

Thus, the statment is false statement as it does not convert into sound energy.

4 0
3 years ago
4NH3+5O2=4NO+6H20 if 32.5 grams of NH3 react with enough oxygen, how many grams of water should form?
Aneli [31]

51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

<h3>How to find the Number of moles ?</h3>

To calculate the number of moles use the formula

Number of moles = \frac{\text{Given Mass}}{\text{Molar Mass}}

                              = \frac{32.5}{17}

                              = 1.9 mol

4NH₃ + 5O₂ → 4NO + 6H₂O

4 mol of NH₃ react with oxygen to given 6 mole of water.

So 1.9 mol of NH₃ produces = \frac{1.9}{4}\times 6

                                              = 2.85 mol of water

Mass of water = Molar Mass of water × Number of moles of water

                        = 18 × 2.85

                        = 51.3 gram

Thus from the above conclusion we can say that 51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

Learn more about the Moles here: brainly.com/question/15356425

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6 0
2 years ago
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² what elemts is it
natita [175]

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When a solution of NaI reacts with a solution of AgNO3, what is the net ionic equation?
Leni [432]

Answer:

Ag⁺(aq) + I⁻(aq) → AgI(s)

Explanation:

Net ionic equation is a way to write a chemical equation in which you are listing only the species that are participating in the reaction.

In the reaction:

AgNO₃(aq) + NaI(aq) → AgI(s) + NaNO₃(aq).

The ionic equation is:

Ag⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + I⁻(aq) → AgI(s) + Na⁺(aq) + NO₃⁻(aq).

Now, listing only the species that are participating in the reaction:

<h3>Ag⁺(aq) + I⁻(aq) → AgI(s)</h3>

3 0
4 years ago
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