Question

4NH3+5O2=4NO+6H20 if 32.5 grams of NH3 react with enough oxygen, how many grams of water should form?

Answer 1

51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

How to find the Number of moles ?

To calculate the number of moles use the formula

Number of moles = $\frac{\text{Given Mass}}{\text{Molar Mass}}$

                              = $\frac{32.5}{17}$

                              = 1.9 mol

4NH₃ + 5O₂ → 4NO + 6H₂O

4 mol of NH₃ react with oxygen to given 6 mole of water.

So 1.9 mol of NH₃ produces = $\frac{1.9}{4}\times 6$

                                              = 2.85 mol of water

Mass of water = Molar Mass of water × Number of moles of water

                        = 18 × 2.85

                        = 51.3 gram

Thus from the above conclusion we can say that 51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

Learn more about the Moles here: brainly.com/question/15356425

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