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3 years ago

Queston

Chemistry

1 answer:

dmitriy555 [2]3 years ago

5 0

Answer:

Explanation:

We know that the molar mass of KOH is 56 gmol-1

Molar mass of Mg(OH)2 is 58.31 g/mol

Now; the balanced reaction equation is; MgCl2 + 2KOH → Mg(OH)2 + 2KCI

Hence;

2 moles of KOH yields 1 mole of Mg(OH)2

4 moles of KOH yields;

4 moles of KOH/1 mol * 1 mole Mg(OH)2 /2 moles KOH * 58.31 g Mg(OH)2 / 1 mole Mg(OH)2

So option c is correct

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How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g/mL?

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General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Density = Mass over Volume

Explanation:

Step 1: Define

D = 13.6 g/mL

54.8 mL Hg

Step 2: Identify Conversions

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Step 3: Find

13.6 g/mL = x g / 54.8 mL

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Step 4: Convert

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Step 5: Check

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