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Arada [10]
2 years ago
12

Queston

Chemistry
1 answer:
dmitriy555 [2]2 years ago
5 0

Answer:

C

Explanation:

We know that the molar mass of KOH is 56 gmol-1

Molar mass of Mg(OH)2 is 58.31 g/mol

Now; the balanced reaction equation is; MgCl2 + 2KOH → Mg(OH)2 + 2KCI

Hence;

2 moles of KOH yields 1 mole of Mg(OH)2

4 moles of KOH yields;

4 moles of KOH/1 mol * 1   mole Mg(OH)2 /2 moles KOH * 58.31 g Mg(OH)2 / 1 mole Mg(OH)2

So option c is correct

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Calculate the number of moles equivalent to 12.7 gram of iodine molecule ​
Alexus [3.1K]

\LARGE{ \boxed{ \purple{ \rm{Answer}}}}

☃️ Chemical formulae ➝ \sf{I_2}

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{Given \: weight}{Molecular \: weight} }}

Solution:

❍ Molecular weight of \sf{I_2}

= 2 × 126.90

= 253.80

= 254 (approx.)

❍ Given weight: 12.7

Then, no. of moles,

⇛ No. of moles = 12.7 / 254

⇛ No. of moles = 0.05 moles

⚘ No. of moles of Iodine molecule in the given weight = <u>0.05</u><u> </u><u>moles </u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

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Read 2 more answers
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