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3 years ago

Queston

Chemistry

1 answer:

dmitriy555 [2]3 years ago

5 0

Answer:

Explanation:

We know that the molar mass of KOH is 56 gmol-1

Molar mass of Mg(OH)2 is 58.31 g/mol

Now; the balanced reaction equation is; MgCl2 + 2KOH → Mg(OH)2 + 2KCI

Hence;

2 moles of KOH yields 1 mole of Mg(OH)2

4 moles of KOH yields;

4 moles of KOH/1 mol * 1 mole Mg(OH)2 /2 moles KOH * 58.31 g Mg(OH)2 / 1 mole Mg(OH)2

So option c is correct

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An ionic compound contains

hodyreva [135]

Answer:

an ionic compound contains ions

Explanation:

7 0

3 years ago

If exactly 59.6 g of nitrogen gas is needed to inflate your air bag to the

Inga [223]

Answer:

We need 92.3 grams of sodium azide

Explanation:

Step 1: Data given

Mass of nitrogen gas = 59.6 grams

Molar mass of nitrogen gas = 28.0 g/mol

Molar mass of sodium azide = 65.0 g/mol

Step 2: The balanced equation

2NaN3 → 2Na + 3N2

Step 3: Calculate moles nitrogen gas

Moles N2 = mass N2 / molar mass N2

Moles N2 = 59.6 grams/ 28.0 g/mol

Moles N2 = 2.13 moles

Step 4: Calculate moles NaN3

for 2 moles NaN3 we'll have 2 moles Na and 3 moles N2

For 2.13 moles N2 we need 2/3* 2.13 = 1.42 moles NaN3

Step 5: Calculate mass NaN3

Mass NaN3 = Moles NaN3 * molar mass NaN3

Mass NaN3 = 1.42 moles * 65.0 g/mol

Mass NaN3 = 92.3 grams

We need 92.3 grams of sodium azide

7 0

3 years ago

Calculate the volume in ml of 0.200 M na2co3 needed to produce 2.00 g of caco3 there is an excess of cacl2

UkoKoshka [18]

Answer:

$V=100mL$

Explanation:

Hello.

In this case, since the chemical reaction is:

$Na_2CO_3+CaCl_2\rightarrow CaCO_3+2NaCl$

We next compute the moles of sodium carbonate from the 2.00 grams of calcium carbonate via their 1:1 mole ratio in the chemical reaction:

$n_{Na_2CO_3}=2.00gCaCO_3*\frac{1molCaCO_3}{100.09gCaCO_3}*\frac{1molNa_2CO_3}{1molCaCO_3} \\\\n_{Na_2CO_3}=0.0200molNa_2CO_3$

Thus, by knowing the molarity, we compute the volume:

$M=\frac{n}{V}\\ \\V=\frac{n}{M}=\frac{0.0200mol}{0.200mol/L}\\ \\V=0.100L*\frac{1000mL}{1L}\\ \\V=100mL$

Best regards.

8 0

3 years ago

How many grams of nitrogen are in 13.6 mol of Fe (NO3)3?

viktelen [127]

mass = mol no. x molar mass
= 13.6 x 56+(3x14)+(9x16)
= 242g

7 0

2 years ago

Read 2 more answers

Significant figures

stira [4]

Answer:

a) 1.6

f)7.51

b)3.9

g)9.2

c)3.1

h)41.9

d)1.959

i)0.29

e)5.2

j)1.112

Explanation:

When you are multiplying or dividing the numbers you take the least amount of significant figures and that's how many significant figures your answer will be. Instead of being a super long answer. Hope this helps. Also, sorry it took me a hot minute :)

8 0

2 years ago