Queston
1 answer:
Answer:
C
Explanation:
We know that the molar mass of KOH is 56 gmol-1
Molar mass of Mg(OH)2 is 58.31 g/mol
Now; the balanced reaction equation is; MgCl2 + 2KOH → Mg(OH)2 + 2KCI
Hence;
2 moles of KOH yields 1 mole of Mg(OH)2
4 moles of KOH yields;
4 moles of KOH/1 mol * 1 mole Mg(OH)2 /2 moles KOH * 58.31 g Mg(OH)2 / 1 mole Mg(OH)2
So option c is correct
You might be interested in
Answer:
4.767 grams of KCl are produced from 2.50 g of K and excess Cl2
Explanation:
The balanced equation is
2 K+ Cl2 --->2 KCI
Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K
Mass of one atom/mole of potassium is 39.098 grams
Number of moles is 2.5 grams =
So, 2 moles of K produces 2 moles of KCL
0.064 moles of K will produces 0.064 moles of KCl
Mass of one molecule of KCl is 74.5513 g/mol
Mass of 0.064 moles of KCl is 4.767 grams