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Amanda [17]
3 years ago
15

The half-life of C-14 is 5470 years. If a particular archaeological sample has one-quarter of its original radioactivity remaini

ng, what is the best estimate for its age?
5470 years

10940 years

16410 years

21880 years
Chemistry
2 answers:
Sever21 [200]3 years ago
6 0

Answer:

When there remains one-quarter of the sample, the age of the sample is 10940 years

Explanation:

Step 1: Data given

The half- life time is the time required for a quantity to reduce to half of its initial value.

The half-life of C-14 is 5470 years.

This means after 5470 years there remains half of the C-14 sample.

When there will pass another half-life cyclus, half of the sample will remain.

Half of 50 % = 25% = one- quarter

This means 2 half-lives should have passed to remain a quarter of the sample.

<u>Step 2</u>: Calculate it's age

t/(t/1/2) = 2

⇒ with t = the age (or time) of the sample

⇒ with t(1/2) = the half-life time of the sample = 5470 years

⇒ with 2 = the number of half- lives passed  to remain one quarter of sample

t/5470 = 2

t = 2*5470 = 10940 years

When there remains one-quarter of the sample, the age of the sample is 10940 years

-Dominant- [34]3 years ago
3 0
10940? Sorry if it isn’t correct
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pickupchik [31]

Answer:

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Explanation:

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The moles of Ca²⁺ can be found using the molar relationship between Ca(NO₃)₂ and Ca²⁺

(0.100mol Ca(NO₃)₂) (Ca²⁺ /Ca(NO₃)₂) = 0.100 mol Ca²⁺

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6 0
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</span>
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Answer:

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