I'll explain with the help of examples:
Solution :<span>is basically two substances that are evenly mixed together. One of them is called the </span>solute <span>and the other is the </span>solvent
Solvent:<span> is the substance to be dissolved (sugar).</span>
Solutes:<span>The </span>solvent<span> is the one doing the dissolving (water)</span>
Answer:
Symbol : S
molecule : S₈
Explanation:
The symbol of an element is just the representation with few alphabets (one or two) with no digit as we don't represent it for an atom or molecule. Just a symbol.
So for example
Symbol for Helium is He
Symbol for hydrogen is H
Symbol for sulfur is S
However the sulfur in nature exist as a molecule with eight atoms of sulfur.
Thus the elemental form of sulfur is an eight atomic molecule
The forms is represented as S₈.
A.0.103M
B. 0.0168mol
C.24.6ml
Work shown in picture
Answer:
%Ionization = 1.63%
Explanation:
Hydrazine in aqueous media theoretically forms a difunctional hydroxyl system. However, for this problem assume only monofunctional ionization occurs. A second hydroxyl ionization would not likely occur as the formal cationic charge formed in the 1st ionization would inhibit a second ionization.
H₂NNH₂ + 2H₂O => HONHNHOH => HONHNH⁺ + OH⁻; Kb = 1.3 x 10⁻⁶
So, assuming all OH⁻ and HONHNH⁺ are delivered in the 1st ionization then a good estimate of the %ionization can be calculated.
HONHNHOH => HONHNH⁺ + OH⁻
C(i) => 0.490M 0M 0M
ΔC => -x +x +x
C(eq) => 0.490 - x x x
≅0.490M* => *x is dropped as Conc H₂NNH₂/Kb > 100
Kb = [HONHNH⁺][OH⁻]/[HONHNHOH]
1.3 x 10⁻⁶ = x²/0.490
=> x = [OH⁻] = [HONHNH⁺] = √[(1.3 x 10⁻⁶)(0.490)] = 8 x 10⁻⁴
=> %Ionization = (x/0.490)100% = (8 x 10⁻⁴/0.490)100% = 1.63%