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jek_recluse [69]
3 years ago
7

When a solution of NaI reacts with a solution of AgNO3, what is the net ionic equation?

Chemistry
1 answer:
Leni [432]3 years ago
3 0

Answer:

Ag⁺(aq) + I⁻(aq) → AgI(s)

Explanation:

Net ionic equation is a way to write a chemical equation in which you are listing only the species that are participating in the reaction.

In the reaction:

AgNO₃(aq) + NaI(aq) → AgI(s) + NaNO₃(aq).

The ionic equation is:

Ag⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + I⁻(aq) → AgI(s) + Na⁺(aq) + NO₃⁻(aq).

Now, listing only the species that are participating in the reaction:

<h3>Ag⁺(aq) + I⁻(aq) → AgI(s)</h3>

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g Enter your answer in the provided box. If 30.8 mL of lead(II) nitrate solution reacts completely with excess sodium iodide sol
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Answer:

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Hello,

In this case, the undergoing chemical reaction is:

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Thus, for 0.904 g of precipitate, that is lead (II) iodide, we can compute the initial moles of lead (II) ions in lead (II) nitrate:

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Regards.

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