All categories

3 years ago

Consider a normally distributed data set with a mean of 75 and a standard deviation of 5. If

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

3 0

Answer:

GOOGLE

Step-by-step explanation:

GOOGLE ATE MY BONEST CHILDREN

You might be interested in

Using the technique in the model above, find the missing sides in this 30°-60°-90° triangle.

lina2011 [118]

For this case what you should do is use the following trigonometric relationship:
sin (x) = C.O / h
Where
x: angle
C.O: opposite leg
h: hypotenuse
Substituting the values we have:
sen (60) = long / h
sen (60) = 3 / h
h = 3 / sin (60)
h = 3.46
Answer:
h = 3.46

7 0

3 years ago

Read 2 more answers

12-km run. How many miles is the run?

elena-14-01-66 [18.8K]

Answer:

the amount of miles in 12km

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which of the following recursive formulas represents the same arithmetic sequence as the explicit formula an=5+(n-1)2?

satela [25.4K]

Answer:

Step-by-step explanation:

In Arithmetic sequence , 2nd term = first term + d

3rd term = 2nd term + d

In this given explicit formula, we can find that d =2

an ----> n th term; an-1 -----> n-1 th term

an = an-1 th term + 2

7 0

3 years ago

Read 2 more answers

HELP ME FAST PLZ ❗️.

vfiekz [6]

Answer:

Step-by-step explanation:

You use law of sines, and get: AB/sin(53) = 7/sin(44)

You multiply both sides by sin(53), and get:

AB = 7*sin(53)/sin(44)

That means AB is 8.04776679886, which rounds to 8

7 0

3 years ago

A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of

cestrela7 [59]

The amount of gas consumed by first and second car were 20 gallons and 15 gallons respectively.

Explanation

Suppose, $x$ gallons of gas were consumed by the first car.

As the total gas consumption in one week is 35 gallons, so the amount of gas consumed by second car will be: $(35-x)$ gallons.

The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas.

So, the distance traveled by the first car in $x$ gallons of gas $=35x$ miles and the distance traveled by the second car in $(35-x)$ gallons of gas $=15(35-x)$ miles.

Given that, the two cars went a combined total of 925 miles. So, the equation will be.....

$35x+15(35-x)=925\\ \\ 35x+525-15x=925\\ \\ 20x=925-525=400\\ \\ x=\frac{400}{20}=20$

So, the amount of gas consumed by the first car is 20 gallons and the amount of gas consumed by the second car is: (35 - 20) = 15 gallons.

3 0

3 years ago