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S_A_V [24]
2 years ago
14

What are the standard units of specific gravity?

Physics
2 answers:
mafiozo [28]2 years ago
8 0

the answer is b.kg/L

the proper answer is 1.0 kg per litre

mr_godi [17]2 years ago
4 0

Answer:

<u><em>The answer is</em></u>: <u>g / cm3.</u>

<u />

Explanation:

Specific gravity <em>is a comparison of the density of a substance with the density of water.</em>

The specific gravity of water at a standard temperature and pressure is considered as one, <em>so if the specific gravity of a substance is five, it means that it is five times denser than water. </em>

<em>It is common that said substance is always water, since it is known that it has</em> 1 gram per milliliter or 1 gram per cubic centimeter.

<u><em>The answer is</em></u>: <u>g / cm3.</u>

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All of Dina's potential energy Ep is converted into kinetic energy Ek so Ep=Ek, where Ep=m*g*h and Ek=(1/2)*m*v². m is the mass of Dina, h is the height of ski slope, g=9.8 m/s² and v is the maximal velocity. 

So we solve for v:

m*g*h=(1/2)*m*v², masses cancel out,

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2 years ago
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VikaD [51]

Answer:

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4 0
3 years ago
A capacitor is charged until its stored energy is 7.54 J. A second capacitor is then connected to it in parallel. If the charge
Ivan

Answer:

2 J

Explanation:

A charged capacitor of capacitance C_1 with energy of 7.54 J, is connected in parallel with another capacitor C_2 , so the charge is equally distributed between them.

(a) The energy stored in the capacitor before it being connected to the other capacitor is:

U_O=q_0^2/2C_1=7.54 J\\

The energy stored in the electric field is the sum of the energies of the two capacitors:

U=U_1+U_2\\U=q_1^2/2C_1+q_2^2/2C_2

since the charge equally distributed,  q_1 = q_2 = q_o/2. and since they are connected in parallel the potential difference on both of them is the same :

V_1=V_2\\q_1/C_1=q_2/C_2\\q_0/C_1=q_0/C_2\\C_1=C_2=C_3\\

hence,

U=q_0^2/8C+q_0^2/8C\\U=q_0^2/4C\\U=2J

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