Answer:
10,000 years
Explanation:
Given that,
Half life of the radioactive isotope, = 5000 years
Initial composition, = 16 grams
Final composition, = 4 grams
We know that,
Therefore, the age of the rock is 10,000 years.
A 1,800 kg car is parked on a road that has an elevation level of 7°. Suppose the coefficient of static friction is .65. What is
the force of static friction?
1 answer:
m = mass of the car = 1800 kg
g = acceleration due to gravity = 9.8 m/s²
= force of gravity on the car
force of gravity on the car is given as
= mg
inserting the values
= (1800) (9.8) = 17640 N
= static frictional force acting on the car
from the force diagram of the car , the static frictional force is opposite to the parallel component of force of gravity on the car . hence static frictional force mus balance the component of force of gravity parallel to incline surface.
hence
=
Sin7
= (17640) Sin7
= 2149.8 N
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Answer:
T = 15.03°C
Explanation:
given data:
copper specific heat = Sc = 0.385 J/g °C
iron specific iron = Si = 0.450 J/g °C
specific heat of ethanol = Se = 2.46 J/g °C
net heat loss is equal to zero
T = 15.03°C
Answer:
About 2.19 seconds
Explanation:
Since the ball is dropped from rest, there is no initial velocity, and you can write the following equation:
Hope this helps!