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Sergio039 [100]

3 years ago

13

a positively charged body makes contact with a body. after a while, the charged body becomes neutralised. state 3 main condition

s for this scenario to occur.

1 answer:

MrRa [10]3 years ago

5 0

Answer:

A body will become positively charged when some electrons will come out from the body.Thus, positive charge is due to deficiency of electrons.

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What is the energy (in joules) of an ultraviolet photon with wavelength 110 nm?

Anon25 [30]

For light or ultraviolet, the formula for energy can be calculated using Planck’s equation. That is:

E = h c / ʎ

where,

h is the Planck’s constant = 6.626 * 10^-34 m^2 kg / s

c is the speed of light = 3 * 10^8 m/s

ʎ is the wavelength of light = 110 nm = 110 x 10^-9 m

So calculating for energy E:

E = (6.626 * 10^-34 m^2 kg / s) * (3 * 10^8 m/s) / (110 x 10^-9 m)

E = 1.807 x 10^-18 J

5 0

3 years ago

2. Consider a conical pendulum with a bob of mass m = 77.0 kg on a string of length L = 10.0 m that makes an angle of ???? 3.00°

bekas [8.4K]

Explanation:

It is given that,

The mass of bob, m = 77 kg

Length of the string, L = 10 m

Angle made by the string with the vertical, $\theta=3^{\circ}$

(a) Let T is the force exerted by the string on the pendulum. At equilibrium,

$T\ cos\theta=mg$

$T=\dfrac{mg}{cos\theta}$

$T=\dfrac{77\times 9.8}{cos(3)}$

T = 755.63 N

The horizontal component of the force is given by,

$T_H=T\ sin\theta$

$T_H=755.63\ sin(3)=39.54\ N$

The vertical component of the force is given by,

$T_V=T\ sin\theta=mg$

$T_V=754.59\ N$

(b) Let a is the radial acceleration of the bob. It can be calculated as :

$a=\dfrac{T_H}{m}$

$a=\dfrac{39.54\ N}{77\ kg}$

$a=0.51\ m/s^2$

Hence, this is the required solution.

6 0

3 years ago

Solar energy is: expensive renewable inefficient during winter all of the above

creativ13 [48]

Solar energy is free and renewable.

Its efficiency is determined by the photovoltaic or heat-exchanging equipment used, and the efficiency of the infrastructure built to interconnect them. None of that depends on the time of the year. For a given amount of solar energy absorbed by the collector, the amount of useful output energy doesn't change with the season.

3 0

3 years ago

Read 2 more answers

What did Thomson’s model of the atom include that Dalton’s model did not have?

astraxan [27]

Answer: Option (d) is the correct answer.

Explanation:

Dalton's model of atom states that every matter is made up of atoms and these atoms are indivisible in nature.

On the other hand, Thomson's model of atom states that there are small particles present in an atom that has positive or negative charges.

Thomson's model of atom is also known as plum pudding model where negatively charged particles are represented by plum and positively charged particles are represented by pudding.

Thus, we can conclude that Thomson’s model of the atom include smaller particles that Dalton’s model did not have.

4 0

3 years ago

Read 2 more answers

Irina finds an unlabeled box of fine needles, and wants to determine how thick they are. A standard ruler will not do the job, a

Vsevolod [243]

Answer:

$d=\frac{1.22\times 640\times 10^{-9}\times 21.7}{7.35\times 10^{-2}}=2305.21\times 10^{-7}m$

Explanation:

The expression which represent the first diffraction minima by a circular aperture is given by $d sin\Theta =1.22\lambda$ --------eqn 1

The angle through which the first minima is diffracted is given by $tan\Theta =\frac{y_1}{D}$ ---------eqn 2

As $\Theta$ is very small so we can write $sin\Theta =tan\Theta$

So from eqn 1 and eqn 2 we can write

$y_1=\frac{1.22\lambda D}{d}$ --------eqn 3

Here $y_1$ is the position of first maxima D is the distance of screen from the circular aperture d is the diameter of aperture

It is given that diameter of circular aperture is 14.7 cm so $y_1=\frac{14.7}{2}=7.35 \ cm$

Now putting all these value in eqn 3

$d=\frac{1.22\lambda D}{y_1}$

$d=\frac{1.22\times 640\times 10^{-9}\times 21.7}{7.35\times 10^{-2}}=2305.21\times 10^{-7}m$

8 0

3 years ago