Answer:
23
Step-by-step explanation:
3.47 = 3 sig. figs.
6.7 = 2 sig. figs.
Since these two numbers are being multiplied, you would round to the smallest number of sig. figs. of the two. In this case, it would be 2 significant figures.
3.47 * 6.7 = 23.249 (dont forget to round to 2 sig. figs. ) --> 23
Answer:
Y=5(x) Yes it is porportional.
Step-by-step explanation:
So lets look at the graph.
We first have 1x = 5y
Well, that makes it seem like for each x there are 5 y.
Lets see the other values:
2x = 10y
Divide both sides by 2 tog et x alone:
1x=5y
Again, for each x, there are 5y.
This is true for each one:
3x=15y
=
1x=5y
4x=20y
=
1x=5y
5x=25y
=
1x=5y
and finally:
6x=30y
=
1x=5y.
So yes, this is poroportional.
It can be shown as x=5y, since for a single x, there are 5 y's.
Hope this helps!
Answer:
Her answer should have been x=17/34
Step-by-step explanation:
Answer: The Total $110
Step-by-step explanation:
I hope this is what you are looking for
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
