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Law Incorporation [45]
3 years ago
7

Which point satisfies the inquality 2×+y > 10 a. (2,3) b.(3,4) c. (3,2) d. (4,3)

Mathematics
1 answer:
Anna11 [10]3 years ago
8 0
D. (4,3) that's the answer
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A. A parabola opening upward, shifted 8 units right, and 5 units down.
Lesechka [4]

Answer:

A) y=(x-8)^2-5

B)y=10(x+6)^2

C) y=-0.6(x+7)^2-2

Step-by-step explanation:

5 0
3 years ago
Write a system of equations to model each situation. Solve using any method:
ivolga24 [154]

Answer:

a=50 b=20

Step-by-step explanation:

Call A and B the 2 present ages.

Ten years from now, A is twice as old as B -->

(A + 10) = 2(B + 10) (1)

Five years ago, A was 3 times as old as B -->

(A - 5) = 3(B - 5) (2).

Solve the system (1) and (2).

From (2) --> A = 3B - 15 + 5 = 3B - 10.

Replace this value of A into (1) -->

3B - 10 + 10 = 2B + 20 --> B = 20. Then,

A = 3B - 10 = 60 - 10 = 50.

Check

!0 years from now --> A = 60 and B = 30 --> A = 2B .OK

5 years ago --> A = 45 and B = 15 --> A = 3B. OK

6 0
3 years ago
From your conclusions in part E, how many triangles can be constructed based on the given conditions?
cricket20 [7]

What are the given conditions?

6 0
3 years ago
Read 2 more answers
First to answer gets brainliest
atroni [7]

Answer:

Last one

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
(2x + 3y) + (4x - 3y) = 11+(-5)
Maurinko [17]

Answer:

The correct option should have been 6x=6.

Step-by-step explanation:

Given the expression

\left(2x\:+\:3y\right)\:+\:\left(4x\:-\:3y\right)\:=\:11+\left(-5\right)

solving the expression

\left(2x\:+\:3y\right)\:+\:\left(4x\:-\:3y\right)\:=\:11+\left(-5\right)

Remove parentheses:  (a) = a

2x+3y+4x-3y=11-5

Group like terms

3y-3y+2x+4x=11-5

Add similar elements

6x=6

It is clear that not a single given option is 6x=6. It means no option is correct. It seems you mistyped the correct options.

The correct option should have been 6x=6.

3 0
2 years ago
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