h(x) = 3 * (2)^x
Section A is from x = 1 to x = 2
h(1) = 3 * (2)^1 = 3 * 2 = 6
h(2) = 3 * (2)^2 = 3 * 4 = 12
so
the average rate of change = (12 - 6)/(2 - 1) = 6
Section B is from x = 3 to x = 4
h(3) = 3 * (2)^3 = 3 * 8 = 24
h(4) = 3 * (2)^4 = 3 * 16 = 48
so
the average rate of change = (48 - 24)/(4 - 3) = 24
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)
the average rate of change of section B is 24 and the average rate of change of section A is 6
So 24/6 = 4
The average rate of change of Section B is 4 times greater than the average rate of change of Section A
It's exponential function, not a linear function; so the rate of change is increasing.
Answer:
its B
Step-by-step explanation:
Answer:
6 groups
Step-by-step explanation:
Divide 187 by 37 to split into groups
It's a decimal of 5.05, so create 6 groups
Normal or natural variations in the quality of production output that are due purely to chance are common causes.
According to the statement
we have to tell about the that cause which effect the quality and production output in the normal and natural variation.
So, For this purpose, we know that the
Common cause variation is present when the control chart of a process measure shows a random pattern of variation with all points within the control limits. When a control chart shows common cause variation, a process measure is said to be in statistical control or stable.
And due to this cause there is a lot of effect on the natural variations in the quality of production output.
So, Normal or natural variations in the quality of production output that are due purely to chance are common causes.
Learn more about common cause variation here
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Answer: 600
Step-by-step explanation:
