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4 years ago

When salt dissolves in water, it seems to disappear. What happens to the salt that makes it no longer visible?

2 answers:

7 0

Answer: The answer is C, The particles of the salt separate from each other and become surrounded by water molecules.

olchik [2.2K]4 years ago

4 0

Answer:

the answer is C. The particles of the salt separate from each other and become surrounded by water molecules.

Explanation:

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How do bubbles support the atomic theory?

Tpy6a [65]

A. The bubbles are lighter than air.
B. There is matter that cannot be seen inside the bubbles.
C. The bubbles will burst before long.
D. The bubbles cannot be broken into smaller pieces.

3 0

3 years ago

The system co2(g) + h2(g) ⇀↽ h2o(g) + co(g) is at equilibrium at some temperature. at equilibrium a 4.00 l vessel contains 1.00

Marina CMI [18]

Answer: The moles of $CO_2$ added to the system is 7.13 moles

Explanation:

We are given:

Moles of $CO_2$ at equilibrium = 1.00 moles

Moles of $H_2$ at equilibrium = 1.00 moles

Moles of $H_2O$ at equilibrium = 2.40 moles

Moles of $CO$ at equilibrium = 2.40 moles

Volume of the container = 4.00 L

Concentration is written as:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}$

The given chemical equation follows:

$CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}$

Putting values in above equation, we get:

$K_c=\frac{(\frac{2.40}{4.00})\times (\frac{2.40}{4.00})}{(\frac{1.00}{4.00})\times (\frac{1.00}{4.00})}\\\\K_c=5.76$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of CO = 0.791 mol/L

Volume of solution = 4.00 L

Putting values in above equation, we get:

$0.791M=\frac{\text{Moles of CO}}{4.00L}\\\\\text{Moles of CO}=(0.791mol/\times 4.00L)=3.164mol$

Extra moles of CO = (3.164 - 2.40) = 0.764 moles

Let the moles of $CO_2$ needed be 'x' moles.

Now, equilibrium gets re-established:

$CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)$

Initial: 1.00 1.00 2.40 2.40

At eqllm: (0.236+x) 0.236 3.164 3.164

Again, putting the values in the expression of $K_c$ , we get:

$5.76=\frac{(\frac{3.164}{4.00})\times (\frac{3.164}{4.00})}{(\frac{0.236+x}{4.00})\times (\frac{0.236}{4.00})}\\\\5.76=\frac{10.011}{0.056+0.236x}\\\\x=7.13$

Hence, the moles of $CO_2$ added to the system is 7.13 moles

4 0

3 years ago

can we stir silver nitrate solution with copper spoon? why or why not? support your answer with reason.

HACTEHA [7]

↪ Hello miss "galaxyu035" here's your answer for the question you wrote.

Answer :

No, we cannot stir silver nitrate solution with a copper spoon because , copper is more reactive than silver. Thus,it would displace silver from the silver nitrate solution forming copper nitrate.

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8 0

4 years ago

Which human body system creates the force that allows the body to move?

klemol [59]

Musculoskeletal system because the mussels help move your bones.

6 0

3 years ago

Read 2 more answers

The three states of matter differ primarily in terms of shape and volume. Describe solids, liquids and gases in these terms.

schepotkina [342]

Answer:

solids have definite shape and volume. liquid have definite volume but not definite shape. gases do not have definite volume as well as definite shape.

8 0

3 years ago