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MrMuchimi
3 years ago
8

The three states of matter differ primarily in terms of shape and volume. Describe solids, liquids and gases in these terms.

Chemistry
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

solids have definite shape and volume. liquid have definite volume but not definite shape. gases do not have definite volume as well as definite shape.

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how does increasing concentration/ temperature/ surface area affect the yield of products in a chemical reaction (not reversible
egoroff_w [7]
Answer:
             <span>Increasing concentration, temperature and surface area will increase the yield of products.

Explanation:
                   Concentration:
                                           
Increase in concentration of reactants will increase the number of reactants per unit volume. Therefore, the probability of collisions will increase hence, it will result in the increase in yield.

                   Temperature:
                                        Increase in temperature increases the kinetic energy of reactants. Therefore, the increase in velocity of reactants results in the collisions with high energy. It makes it feasible for reactants to attain the optimum energy (activation energy) to convert into products with good yield.

                  Surface Area:
                                       The reactants in grinded / powder form reacts fast as compared to solid form. In fact, grinding results in increase of the surface area of reactants. Greater surface area increases the probability of reactants to colloid. Hence, increases the yield.</span>
6 0
3 years ago
Is air homogeneous or heterogeneous?
ivolga24 [154]

Answer:  yes, Air is a homogeneous mixture of the gaseous substances nitrogen, oxygen, and smaller amounts of other substances. Salt, sugar, and substances dissolve in water to form homogeneous mixtures. A homogeneous mixture in which there is both a solute and solvent present is also a solution

Explanation:

8 0
2 years ago
Read 2 more answers
A neutral atom in the ground state of Sulfur has its outer most valence electron in which orbital? f d
Natasha_Volkova [10]

<u>Answer:</u> The outermost valence electron enters the p orbital.

<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in outer most orbital of an atom.

Sulfur is the 16th element of the periodic table having 16 electrons.

Electronic configuration of sulfur atom is 1s^22s^22p^63s^23p^4

The number of valence electrons are 2 + 4 = 6

These 6 electrons enter s-orbital and p-orbital but the outermost valence electron will enter the p-orbital.

Hence, the outermost valence electron enters p orbital.

3 0
3 years ago
What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?
White raven [17]

Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

                           Al^{3+}+H_2O\rightarrow Al(OH)^{2+}+H^+

Initial conc.       0.450                   0               0

At eqm.           (0.450-x)                 x               x

As we are given:

K_a=1.00\times 10^{-5}

The expression for equilibrium constant is:

K_a=\frac{(x)\times (x)}{(0.450-x)}

Now put all the given values in this expression, we get:

1.00\times 10^{-5}=\frac{(x)\times (x)}{(0.450-x)}

x=0.00212M

The concentration of H^+ = x = 0.00212 M

Now we have to calculate the pH of solution.

pH=-\log [H^+]

pH=-\log (0.00212)

pH=2.67

Therefore, the pH of the solution is, 2.67

8 0
3 years ago
what is the specific heat of a substance if 300 j are required to raise the temperature of a 267-g sample by 12 degrees c
slava [35]

Answer : The specific heat of the substance is 0.0936 J/g °C

Explanation :

The amount of heat Q can be calculated using following formula.

Q = m \times C \times \bigtriangleup T

Where Q is the amount of heat required = 300 J

m is the mass of the substance = 267 g

ΔT is the change in temperature = 12°C

C is the specific heat of the substance.

We want to solve for C, so the equation for Q is modified as follows.

C = \frac{Q}{m \times \bigtriangleup T}

Let us plug in the values in above equation.

C = \frac{300J}{267g \times 12 C}

C = \frac{300J}{3204 g C}

C = 0.0936 J/g °C

The specific heat of the substance is 0.0936 J/g°C

3 0
3 years ago
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