The neutralization reactions always produced which compound?

2. If heat is released from water vapor, what phase change occurs? (hint: think about what happens when you take away heat/decre

OleMash [197]

Condensation, because it is a phase change from gas to liquid

4 0

3 years ago

S- 2500m

natulia [17]

Answer:

1632 Hz

Explanation:

We'll begin by calculating the frequency of each wave. This can be obtained as follow:

1st wave:

Velocity (v) = 340 m/s.

Wavelength 1 (λ₁) = 5 m

Frequency 1 (f₁) =?

v = λ₁f₁

340 = 5 × f₁

Divide both side by 5

f₁ = 340 / 5

f₁ = 68 Hz

2nd wave:

Velocity (v) = 340 m/s.

Wavelength 2 (λ₂) = 0.2 m

Frequency 2 (f₂) =?

v = λ₂f₂

340 = 0.2 × f₂

Divide both side by 0.2

f₂ = 340 / 0.2

f₂ = 1700 Hz

Finally, we shall determine the difference in the frequency of both waves.

This can be obtained as follow:

Frequency 1 (f₁) = 68 Hz

Frequency 2 (f₂) = 1700 Hz

Difference =?

Difference = f₂ – f₁

Difference = 1700 – 68

Difference = 1632 Hz

8 0

3 years ago

A lab scientist cools a liquid sample of water (2.6 kg) at 0.00°C to -192°C. The water turns to ice as this temperature change o

soldier1979 [14.2K]

Answer: The heat released for the given process is -1892 kJ

Explanation:

The processes involved in the given problem are:

$1.)H_2O(l)(0^oC,273K)\rightarrow H_2O(s)(0^oC,273K)\\2.)H_2O(s)(0^oC,273K)\rightarrow H_2O(s)(-192^oC,81K)$

Pressure is taken as constant.

To calculate the amount of heat released at same temperature, we use the equation:

$q=m\times L_{f,v}$ ......(1)

where,

q = amount of heat released = ?

m = mass of water/ice

$L_{f,v}$ = latent heat of fusion or vaporization

To calculate the amount of heat released at different temperature, we use the equation:

$q=m\times C_{p,m}\times (T_{2}-T_{1})$ .......(1)

where,

q = amount of heat released = ?

$C_{p,m}$ = specific heat capacity of medium

m = mass of water/ice

$T_2$ = final temperature

$T_1$ = initial temperature

Calculating the heat absorbed for each process:

For process 1:

Converting the latent heat of fusion in J/kg, we use the conversion factor:

1 kJ = 1000 J

So, $(\frac{-334kJ}{1kg})\times (\frac{1000J}{1kJ})=-334\times 10^3J/kg$

We are given:

$m=2.6kg\\L_f=-334\times 10^3J/kg$

Putting values in equation 1, we get:

$q_1=2.6kg\times (-334\times 10^3J/kg)=-868400J$

For process 2:

We are given:

$m=2.6kg\\C_{p,s}=2050J/kg.K\\T_1=273K\T_2=81K$

Putting values in equation 2, we get:

$q_2=2.6kg\times 2050J/kg.K\times (81-(273))^oC\\\\q_2=1023360J$

Total heat absorbed = $q_1+q_2$

Total heat absorbed = $[-868400+(-1023360)]J=-1891760J=-1891.76kJ\approx -1892kJ$

Hence, the heat released for the given process is -1892 kJ

3 0

3 years ago

Under which conditions will sugar most likely dissolve fastest in a cup of water?

zheka24 [161]

If the cup of water contained hot water. Sugar will dissolve a lot slower if it was in room temperature and even slower if it was in cold water.

3 0

3 years ago

Consider the reaction below. Mg(s) + 2HCl(aq) mc019-1.jpg H2(g) + MgCl2(aq) What is the most likely effect of an increase in pre

bonufazy [111]

1) Reaction:

Mg(s) + 2HCl (aq) ----> H2(g) + MgCl2(aq)

2) Analysis

An increase in pressure affects directly the rate of reaction involving reactiong gases. Changing the pressure where there are only solids or liquids does not affect the rate of reaction.

This reaction is not an equilibrium, the reaction is only forward. So, the reacting components, Mg(s) and HCl(aq) are a solid and a liquid.

Therefore, the reaction is not affected by the change in pressure.

Answer: the reaction is not affected at all.

4 0

3 years ago

Read 2 more answers