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3 years ago

If oxygen, symbol o, undergoes a covalent bond it wants to form how many bonds

Chemistry

2 answers:

Marysya12 [62]3 years ago

7 0

Answer: 2.

Explanation:

1) The number of bonds that an atom is willing to form may be predicted in terms of the octet rule.

2) Atomic number of oxygen is 8, which implies that the atom has 8 electrons.

3) The electron configuration of oxygen is 1s² 2s² 2p⁴.

4) So, oxygen has 6 electrons in its valence shell.

5) The octet rule states that any atom will try to reach the configuration of the closest noble gas by "gaiing" or "giving" the electrons to have the 8 electrons in the outer shell.

6) Then oxygen will be willing to share two electrons with other atoms to complete, along with its own 6 electrons, the 8 electrons, which leads to the configuration of the noble gas Ne.

7) Each electron shared contributes to the formation of a bond. That is why by sharing two electrons, oxygen will form two covalent bonds.

polet [3.4K]3 years ago

5 0

Oxygen has 16 bonds in total

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3 years ago

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Answer:

_5_ AsO2−(aq) + 3 Mn2+(aq) + _2_ H2O(l) → _5_ As(s) + _3_ MnO4−(aq) + _4_ H+(aq)

Explanation:

Step 1:

The unbalanced equation:

AsO2−(aq) + 3 Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

Step 2:

Balancing the equation.

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

The above equation can be balanced as follow:

There are 3 atoms of Mn on the left side of the equation and 1 atom on the right side. It can be balance by putting 3 in front of MnO4− as shown below:

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 12 atoms of O on the right side and a total of 3 atoms on the left side. It can be balance by putting 5 in front of AsO2− and 2 in front of H2O as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

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3 years ago

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