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3 years ago

If oxygen, symbol o, undergoes a covalent bond it wants to form how many bonds

Chemistry

2 answers:

Marysya12 [62]3 years ago

7 0

Answer: 2.

Explanation:

1) The number of bonds that an atom is willing to form may be predicted in terms of the octet rule.

2) Atomic number of oxygen is 8, which implies that the atom has 8 electrons.

3) The electron configuration of oxygen is 1s² 2s² 2p⁴.

4) So, oxygen has 6 electrons in its valence shell.

5) The octet rule states that any atom will try to reach the configuration of the closest noble gas by "gaiing" or "giving" the electrons to have the 8 electrons in the outer shell.

6) Then oxygen will be willing to share two electrons with other atoms to complete, along with its own 6 electrons, the 8 electrons, which leads to the configuration of the noble gas Ne.

7) Each electron shared contributes to the formation of a bond. That is why by sharing two electrons, oxygen will form two covalent bonds.

polet [3.4K]3 years ago

5 0

Oxygen has 16 bonds in total

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Answer: Option (b) is the correct answer.

Explanation:

A covalent compound is defined as the compound in which sharing of electrons take place between the combining atoms. Generally, when two or more non-metals chemically combine together the it will lead to the formation of a covalent compound.

For example, $C_{6}H_{12}O_{6}$ and HCl is also a covalent compound.

And, a compound in which transfer of electrons occur between the combining atoms is known as an ionic compound. Whenever, a metal chemically combines with a non-metal then it will always lead to the formation of an ionic compound.

For example, KI is an ionic compound.

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3 years ago

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Answer:

letter D.

Explanation:

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2 years ago

Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda re

Setler [38]

Answer:

0.5 mole of CO₂.

Explanation:

We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:

Mass of NaHCO₃ = 42 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 42/84

Mole of NaHCO₃ = 0.5 mole

Next, balanced equation for the reaction. This is given below:

NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

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