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worty [1.4K]
2 years ago
15

Look at the diagram. De both lemas and humans have the traits listed at point D? Explain your reasoning​

Chemistry
1 answer:
Bogdan [553]2 years ago
3 0

Answer:

WHAT DIAGRAM THX FOR POINTS THO

Explanation:

You might be interested in
What is uranium classified as
Free_Kalibri [48]

Answer:

uranium is classifide as actinide a chemical element atomic number 92 and is a solid at room temperature

7 0
2 years ago
How many electron pairs are shared by an oxygen molecule?​
Lana71 [14]

Two electron pairs is the answer

6 0
3 years ago
Acetylsalicylic acid (aspirin), HC9H7O4, is the most widely used pain reliever and fever reducer. Find the pH of 0.035 M aqueous
KatRina [158]

<u> </u> The pH of 0.035 M aqueous aspirin is 2.48

<u>Explanation:</u>

We are given:

Concentration of aspirin = 0.035 M

The chemical equation for the dissociation of aspirin (acetylsalicylic acid) follows:

               HC_9H_7O_4\rightleftharpoons H^++C_9H_7O_4^-

<u>Initial:</u>         0.035

<u>At eqllm:</u>    0.035-x        x         x

The expression of K_a for above equation follows:

K_a=\frac{[C_9H_7O_4^-][H^+]}{[HC_9H_7O_4]}

We are given:

K_a=3.6\times 10^{-4}

Putting values in above expression, we get:

3.6\times 10^{-4}=\frac{x\times x}{(0.035-x)}\\\\x=-0.0037,0.0033

Neglecting the value of x = -0.0037 because concentration cannot be negative

So, concentration of H^+ = x = 0.0033 M

  • To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

H^+ = 0.0033 M

Putting values in above equation, we get:

pH=-\log(0.0033)\\\\pH=2.48

Hence, the pH of 0.035 M aqueous aspirin is 2.48

7 0
3 years ago
Find the total mass of three diamonds that have masses of 14.2 grams, 8.73 grams, and 0.912 gram
GaryK [48]
The total mass means that you need to add up all three diamonds' mass. So the calculation equation is 14.2+8.73+0.912 = 23.842 g.
7 0
3 years ago
Determine if the electron configurations are valid or invalid
Hunter-Best [27]

Answer:

1) A (valid)

2) B (Invalid)

3) B (Invalid)

4) A (valid)

5) B (Invalid)

6) B (Invalid)

Explanation:

Electronic configuration:

The electronic configuration is the arrangnment of electrons in orbitals (s, p, d, f, g, h so on) according to quantum  number and Aufbau rule.

An atom of element have orbitals, and electrons are revolving in it.

There are quantum numbers that describe the number of electron in specific shell.

The Principle quantum number is denoted by "n" and can not be "0".

These "n" is K, L, M, N and electrons are distribution in it.

K =2

L= 8

M= 18

According to Aufbau electron occupied in the lowest energy level before occupying the highest energy level.

According to this the electronic configuration is

1s², 2s², 2p⁶ and so on....

So,

"s" orbital accommodate maximum of 2 electrons

"p" orbital accommodate maximum of 6 electrons

"d" orbital accommodate maximum of 10 electrons

"f" orbital accommodate maximum of 14 electrons

and the coefficient 1, 2, 3, 4 are energy level of orbitals.

The 1st orbital is 1s and it only can occupy 2 electrons the next coming electron goes into 2s that also can occupy 2 electrons and the further electrons will go to 2p orbital.

So keeping in mind all above details we investigate all option one by one

1.  A (valid)

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁵

This is valid option. number of electrons are rightly accommodated in orbitals. Also 3d is higher energy level than 4p.

______________

2.  B (Invalid)

1s², 2s², 2p⁶, 3s², 3p⁷

This is invalid option. number of electrons are not rightly accommodated in orbitals as "p" orbital can only accommodate 6 electrons and not more than 6.

________________

3.  B (Invalid)

[Xe], 7s², 6d¹, 5f⁸

This is Invalid option. Number of electrons are not rightly accommodated in orbitals. There should 5f orbital before 6d.

______________

4.  A (valid)

[Kr] 5s², 4d¹⁰, 5p⁵

This is valid option. number of electrons are rightly accommodated in orbitals.

______________

5.  B (Invalid)

[He]--

This is invalid option. There is no exact explanation of electron distribution in orbitals.

______________

6.  B (Invalid)

1s², 2s², 2p⁶, 3s³, 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s--

This is invalid option. number of electrons are not rightly accommodated in orbitals. As "s" can accommodate only 2 electrons not 3 electrons. also there is no details of 5s

______________

4 0
3 years ago
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