The concentration of the drug stock solution is 1.5*10^-9 M i.e. 1.5 * 10^-9 moles of the drug per Liter of the solution
Therefore, the number of moles present in 1 ml i.e. 1*10^-3 L of the solution would be = 1 *10^-3 L * 1.5 * 10^-9 moles/1 L = 1.5 * 10^-12 moles
1 mole of the drug will contain 6.023*10^23 drug molecules
Therefore, 1.5*10^-12 moles of the drug will correspond to :
1.5 * 10^-12 moles * 6.023*10^23 molecules/1 mole = 9.035 * 10^11 molecules
The number of cancer cells = 2.0 * 10^5
Hence the ratio = drug molecules/cancer cells
= 9.035 *10^11/2.0 *10^5
= 4.5 * 10^6
The answer for the following problem is mentioned below.
- <u><em>Therefore the final temperature of the gas is 740 K</em></u>
Explanation:
Given:
Initial pressure of the gas (
) = 1.8 atm
Final pressure of the gas (
) = 4 atm
Initial temperature of the gas (
) = 60°C = 60 + 273 = 333 K
To solve:
Final temperature of the gas (
)
We know;
From the ideal gas equation;
we know;
P × V = n × R × T
So;
we can tell from the above equation;
<u> P ∝ T</u>
(i.e.)
<em> </em>
<em> = constant</em>
= 
Where;
= initial pressure of a gas
= final pressure of a gas
= initial temperature of a gas
= final temperature of a gas
= 
=
= 740 K
<u><em>Therefore the final temperature of the gas is 740 K</em></u>
Answer:
<h3>The answer is 3.0 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 15 g
volume = 5 mL
We have

We have the final answer as
<h3>3.0 g/mL</h3>
Hope this helps you
I think it's Letter c.13 if I'm not mistaken
Complete Question
The diagram for this question is shown on the second uploaded image
Answer:
The organic product obtained is shown on the first uploaded image
Explanation:
The process that lead to this product formation is known as oxidative cleavage which is a reaction that involves the cleavage of a carbon to carbon bond at the same time this carbon which formed the carbon bond are oxidized i.e oxygen is been added to them