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nlexa [21]
2 years ago
14

On the first day of school, a class of th-grade students are given tour identical cubes of hard clay. The cubes are placed in fo

ur different conditions until the last day of school. At that time, the students make the following
Observations
Sample 1 classroom cabinet - no noticeable changes
Sample 2 near a window lighter in color
Sample 3: freezer small cracks near comers
Sample 4: bottle of water - small amount of algae on top Which sample shows evidence of physical weathering?
Samolot
Samole
0 0 0
Samples
Sample 4
Chemistry
1 answer:
matrenka [14]2 years ago
6 0

Answer:

sample 4

Explanation:

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What is technological design useful for?
valkas [14]

Answer:

The process of designing a new technology includes much more than just coming up with a good idea. Possible limitations, or constraints

Explanation:

hope it helps alot

7 0
3 years ago
What happened to the reaction below
Citrus2011 [14]

c the temperature is increased?5)

3 0
3 years ago
How is the concentration of h3o ions and oh- ions different in an acid solution and a basic soulution?
Lubov Fominskaja [6]
In an acidic solution, the concentration of H+ is greater than the concentration of OH-. The pH will be less than 7.
In a basic solution, the concentration of OH- is greater than the concentration of H+. The pH will be greater than 7.
In a neutral solution, the concentration of H+ ions to OH-ions will be equal, and will therefore have a pH of 7. (This is due to water autoionization, which we usually ignore because it is small in other circumstances.)
5 0
3 years ago
A 0.45-g sample of aspirin is decomposed into its constituent elements and found to contain 0.27 g C, 0.020 g H, and 0.16 g O. C
slamgirl [31]

Answer:

Explanation:

mass % of C = 0.27/0.45*100 = 60%

mass % of H = 0.02/0.45*100 = 4.4%

mass % of O = 0.16/0.45*100 = 35.6%

Total = 60%+4.4%+ 35.6% = 100%

3 0
3 years ago
2. A student has a centrifuge tube containing 14.0 g of t-butanol and is asked to make a 1.2 m solution of ethanol/t-butanol. Ho
Vaselesa [24]

Answer:

0.774g of ethanol

0.970mL of ethanol

Explanation:

Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.

In the problem, you need to prepare a 1.2m solution of ethanol (Solute) in t-butanol (solvent).

14.0g of butanol are <em>0.014kg </em>and as you want to prepare the 1.2m solution, you need to add:

0.014kg × (1.2moles / kg) = 0.0168 moles of solute = Moles of ethanol

To convert moles of ethanol to mass you require molar mass (Molar mass ethanol, C₂H₅OH = 46.07g/mol). Thus, mass of 0.0168 moles are:

0.0168moles Ethanol ₓ (46.07g / mol) =

<h3>0.774g of ethanol</h3>

And to convert mass in g to mL you require density of the substance (Density of ethanol = 0.798g/mL):

0.774g ₓ (1mL / 0.798g) =

<h3>0.970mL of ehtanol</h3>
8 0
2 years ago
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