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nlexa [21]
3 years ago
14

On the first day of school, a class of th-grade students are given tour identical cubes of hard clay. The cubes are placed in fo

ur different conditions until the last day of school. At that time, the students make the following
Observations
Sample 1 classroom cabinet - no noticeable changes
Sample 2 near a window lighter in color
Sample 3: freezer small cracks near comers
Sample 4: bottle of water - small amount of algae on top Which sample shows evidence of physical weathering?
Samolot
Samole
0 0 0
Samples
Sample 4
Chemistry
1 answer:
matrenka [14]3 years ago
6 0

Answer:

sample 4

Explanation:

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Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
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<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

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Shells (electrons) - located in the cloud
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level 2 - 8 electrons
level 3- 18 electrons)

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