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3 years ago

12

500 grams of a soil is taken and dried completely in bright sunshine. The mass of dried soil is found to be 450 grams. The perce

ntage of water present in the given sample of soil is: (1 Point) 15% 5% 10%

1 answer:

satela [25.4K]3 years ago

4 0

The Correct Answer Is 15% Since The Mass Of The Dried Soil Is 170g.

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Which two compounds are classified as bases by the Brønsted-Lowry definition, but not by the Arrhenius definition, and why?

konstantin123 [22]

Answer: Ammonia (NH3) and sodium carbonate (Na2CO3), because they accept hydrogen ions but lack hydroxide ions.

Explanation:

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3 years ago

The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime

krok68 [10]

Answer: The rate constant for the reaction is $3.96\times 10^{-3}min^{-1}$

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = $2.83\times 10^{-3}$

a - x = amount left after decay process = $3.06\times 10^{-4}$

$559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}$

$k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}$

$k=3.96\times 10^{-3}min^{-1}$

The rate constant for the reaction is $3.96\times 10^{-3}min^{-1}$

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3 years ago

GenaCL600 [577]

Answer:

answer is 76

Explanation:

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3 years ago

How fast do p waves travel ?

Amanda [17]

Answer:

Between 1 and 14 km/sec

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3 years ago

For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomas

Flauer [41]

Answer:

4.25% is the final concentration of phosphoric acid.

Explanation:

Initial concentration of phosphoric acid = $C_1=85\%=0.85$

Initial volume of phosphoric acid = $V_1=50 mL$

Final concentration of phosphoric acid = $C_2=?$

Final volume of phosphoric acid = $V_2=1 L=1000 mL$

( 1L = 1000 mL)

$C_1V_1=C_2V_2$

$C_2=\frac{C_1times V_1}{V_2}$

$=\frac{0.85\times 50 mL}{1000 mL}=0.0425=4.25%$

4.25% is the final concentration of phosphoric acid.

4 0

3 years ago