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3 years ago

Property of a substance

Chemistry

1 answer:

Scrat [10]3 years ago

8 0

There are many properties to substances.

I'll list some examples below:

Mass
Volume
Density
Conductivity
Malleability
Boiling point
Melting point
Heat capacity

Hope this helps! :3

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How much heat is transferred when during a reaction, 531 g of water increases from 22.7 ○C to 38.8 ○C?

vazorg [7]

Answer:

8.55 × 10³ cal

Explanation:

Step 1: Given and required data

Mass of water (m): 531 g

Specific heat of water (c): 1 cal/g.°C

Initial temperature: 22.7 °C

Final temperature: 38.8 °C

Step 2: Calculate the temperature change (ΔT)

ΔT = Final temperature - Initial temperature = 38.8 °C - 22.7 °C = 16.1 °C

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 1 cal/g.°C × 531 g × 16.1 °C = 8.55 × 10³ cal

8 0

3 years ago

1. Define action energy.

WARRIOR [948]

Answer:

In physics, action is an attribute of the dynamics of a physical system from which the equations of motion of the system can be derived through the principle of stationary action. ... Action has dimensions of energy⋅time or momentum⋅length, and its SI unit is joule-second.

Explanation:

hope it helps

6 0

3 years ago

Read 2 more answers

What mass of oxygen (O2) forms in a reaction that forms 15.90 g C6H12O6?

Genrish500 [490]

To answer this question, you need to know the chemical equation for making glucose. It should be look like this

C6H12O6<span>(s) + 6O2(g) -->6CO2(g) + 6H2O(g)

In the equation, the amount of glucose (</span>C6H12O6) is 1 and the amount of oxygen(O2) is 6. But the equation ratio is using moles as a unit. A mole of glucose will weight 180g but a mole of oxygen weight 32g.

Then, the amount of oxygen forms would be: 6/1 * (15.90g/180g) * 32g= 16.96 grams

4 0

4 years ago

Read 2 more answers

Using the following equation 5KNO2+2KMnO4+3H2SO4=5KNO3+2MnSO4+K2SO4+3H20. Starting with 2.47 grams of KNO2 and excess KMnO4 how

Aleonysh [2.5K]

Given equation : $5KNO_{2} + 2KMnO_{4} + 3H_{2}SO_{4}\rightarrow 5KNO_{3} + 2MnSO_{4} + K_{2}SO_{4} + 3H_{2}O$

Given information = 2.47 grams KNO2 and excess KMnO4 and we need to find grams of water (H2O).

Since KMnO4 is in excess, so grams of water(H2O) can be calculated using grams of KNO2 with the help of stoichiometry.

To find grams of water(H2O) from grams of KNO2 , we need to follow three steps.

Step 1. Convert 2.47 grams of KNO2 to moles of KNO2.

$Moles = \frac{grams}{molar mass}$

Molar mass of KNO2 = 85.10 g/mol

$Moles = 2.47 gram KNO2\times \frac{1 mol KNO2}{85.10 gram KNO2}$

Moles = 0.0290 mol KNO2

Step 2. Convert moles of KNO2 to moles of H2O using mole ratio.

Mole ratio are the coefficient present in front of the compound in the balanced equation.

Mole ratio of KNO2 : H2O is 5 : 3 (5 coefficient of KNO2 and 3 coefficient of H2O)

$0.0290 mol KNO2\times \frac{3 mol H2O}{5 mol KNO2}$

Mole = 0.0174 mol H2O

Step 3. Convert mole of H2O to grams of H2O

Grams = Moles X molar mass

Molar mass of H2O = 18.00 g/mol

$Grams = 0.0174 mol H2O\times \frac{18 g H2O}{1 mol H2O}$

Grams of water = 0.313 grams H2O

Summary : The above three steps can also be done in a singe setup as shown below.

$2.47 gram KNO2\times \frac{(1 mol KNO2)}{(85.10 gram KNO2)}\times \frac{(3 mol H2O)}{(5 mol KNO2)}\times \frac{(18.00 gram H2O)}{(1mol H2O)}$

In the above setup similar units get cancelled out and we will get grams of H2O as 0.313 grams water (H2O)

8 0

4 years ago

2kl(aq)+cl(g) 2kcl (aq) +l2(g) how many moles of L2 are produced

Ksenya-84 [330]

<span>Coefficients in the reaction show numbers of moles in with substances are react or form.
2Kl(aq)+Cl2(g) ----> 2KCl (aq) + l2(g)
2 mol 1 mol 2 mol 1 mol
If we look at the reaction we can see that from 2 mol KI and 1 mol Cl2, form 2 mol KCl and 1 mol I2.</span>

5 0

3 years ago