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cluponka [151]
2 years ago
9

Property of a substance

Chemistry
1 answer:
Scrat [10]2 years ago
8 0

There are many properties to substances.

I'll list some examples below:

  • Mass
  • Volume
  • Density
  • Conductivity
  • Malleability
  • Boiling point
  • Melting point
  • Heat capacity

Hope this helps! :3

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If the first isotope has a mass of 259.98 amu and a percent abundance of 35%, what is the percent abundance of the second isotop
brilliants [131]
If it is assumed that there are only two isotopes then the percent abundance needs to add up to 100%

100-35= 65%

The second isotope will have a 65% abundance.
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3 years ago
R is the midpoint of FG.<br><br> FR = 26 find RG
vichka [17]

Answer:

52

Explanation:

This is because if R is the midpoint of FRG, FR is half of FRG, so basically all you do it multiply by 2 to get the FRG

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2 years ago
Which element has chemical properties that are most<br> similar to potassium, And why?
bekas [8.4K]

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Brainliest pls

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8 0
1 year ago
Question is in the image
zloy xaker [14]

Answer:(3)

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Use the following half-reactions to write three spontaneous reactions, calculate E°cell for each reaction, and rank the oxidizin
Ainat [17]

Answer:

See explaination

Explanation:

1)

we know that

half cell with higher reduction potential is cathode

so

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

anode :

Cr(s) ---> Cr+3 + 3e-

so

overall reaction is

3 N20 + 6H+ + 2 Cr ---> 3N2 + 3H20 + 2Cr+3

now

Eo cell = Eo cathode - Eo anode

so

EO cell = 1.77 + 0.74

Eo cell = 2.51 V

now

in this case

oxidizing agents are N20 and Cr+3

reducing agents are Cr and N2

higher the reduction potential , stronger the oxidizing agent

lower the reduction potential , stronger the reducing agent

so

oxidzing agents

N20 > Cr+3

reducing agents

Cr > N2

2)

cathode :

Au+ + e- --> Au

anode :

Cr ---> Cr+3 + 3e-

overall reaction

3Au+ + Cr ---> 3Au + Cr+3

Eo cell = 1.69 + 0.74

Eo cell = 2.43

now

oxidizing agents :

Au+ > Cr+3

reducing agents :

Cr > Au

3)

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

andoe :

Au ---> Au+ + e-

overall

2 Au + N20 + 2H+ --> 2 Au+ + N2 + H20

Eo cell = 1.77 - 1.69

Eo cell = 0.08

oxidizing agents

N20 > Au+

reducing agents

Au > N2

8 0
3 years ago
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