Complete question :
Edward bought 3 packages of hot dogs with 8 hot dogs in each package.He also bought 3 bags of hot dog buns 4 in each bag. Six people were hving lunch at his home, including eddward.How many hot dogs with bns could each of them have>
Answer:
4 hot dogs and 2 hot dog buns each
Step-by-step explanation:
Number of packages = 3
Number of hotdog package = 8
Total number of hotdogs = 8 * 3 = 24
Hot dog buns = 4 per bag
Buns = 4 * 3 = 12 buns
Hence the 6 could each have :
Hotdogs = 24 /6 = 4
Buns = 12 /6 = 2
4 hot dogs and 2 hot dog buns each
Answer:
<em>36 </em>
Step-by-step explanation:
m∠PQS = m∠PQR - m∠SQR = 70° - 34° = <em>36 </em>°
together = add
add the fractions
3 7/10 + 5 9/10
add the whole numbers first
3+5=8
add the fractions
7/10+9/10= 16/10
8 16/10
reduce 16/10 divide by 2
16/2= 8
10/2= 5
8 8/5
whole number changes to 9
8-5=3
denominator stays the same
9 3/5
Answer:
9 3/5
