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tatuchka [14]
3 years ago
9

Rashida bought 3 tickets to a concert for $75.A this rate how much would 5 tickets cost

Mathematics
2 answers:
frozen [14]3 years ago
6 0
First divide 75 by 3 to figure out what the cost of 1 ticket is.
75÷3 = 25
so, 1 ticket costs $25
now multiply 25 by 5
25*5= 125
so 5 tickets would cost $125
Vaselesa [24]3 years ago
5 0

Answer: The cost of 5 tickets =  $125

Step-by-step explanation:

We are given that , the cost of 3 tickets = $ 75

Then , By Unitary ,method

The cost of one ticket= (cost of 3 tickets) ÷ (3)

= ($75) ÷ (3)

= $25

Now , if the rate is same , the cost of 5 such tickets will be

5 x (Cost of one ticket)

= 5 x ($25)

= $125

Hence , the cost of 5 tickets =  $125

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rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





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3 years ago
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