Let x gallons be the amount of pure antifreeze that should be added to the 30% solution to produce a solution that is 65% antifreeze. Then the total amount of antifreeze solution will be x+3 gallons.
There are 30% of pure antifreeze in 3 gallons of solution, then
3 gallons - 100%,
a gallons - 30%,
where a gallons is the amount of pure antifreeze in given solution.
Mathematically,
Now in new solution there will be x+0.9 gallons of pure antefreeze.
x+3 gallons - 100%,
x+0.9 - 65%
or
Answer: he should add 3 gallons of pure antifreeze.
Answer:
E.1.06(26.50+10d)
Step-by-step explanation:
d+e
i think i its d im not sure to
Answer:-24
Step-by-step explanation:
6+(-5-7) ➗ 2-8(3)
6-12 ➗ 2-24
6-6-24
0-24=-24
Answer:
38 quarters
Step-by-step explanation:
0.25 x 63 = 15.75
0.05 x 63 = 3.15
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0.25 x 50 = 12.50
+ = $13.15
0.05 x 13 = 0.65
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0.25 x 25 = 6.25
+ = $8.15
0.05 x 38 = 1.90
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0.25 x 30 = 7.50
+ = $9.15
0.05 x 33 = 1.65
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0.25 x 35 = 8.75
+ = $10.15
0.05 x 28 = 1.40
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0.25 x 38 = 9.50
+ = $10.75
0.05 x 25 = 1.25
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I hope this helps!
