Question

Solve each polynomial equation by factoring 4x^3+7x^2-5x=6

Answer 1

$4x^3+7x^2-5x=6\\ 4x^3+7x^2-5x-6=0\\ 4x^3+8x^2-x^2-2x-3x-6=0\\ 4x^2(x+2)-x(x+2)-3(x+2)=0\\ (4x^2-x-3)(x+2)=0\\ (4x^2-4x+3x-3)(x+2)=0\\ (4x(x-1)+3(x-1))(x+2)=0\\ (4x+3)(x-1)(x+2)=0\\ x=-\dfrac{3}{4} \vee x=1 \vee x=-2$