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3 years ago

Solve each polynomial equation by factoring 4x^3+7x^2-5x=6

1 answer:

3 0

$4x^3+7x^2-5x=6\\
4x^3+7x^2-5x-6=0\\
4x^3+8x^2-x^2-2x-3x-6=0\\
4x^2(x+2)-x(x+2)-3(x+2)=0\\
(4x^2-x-3)(x+2)=0\\
(4x^2-4x+3x-3)(x+2)=0\\
(4x(x-1)+3(x-1))(x+2)=0\\
(4x+3)(x-1)(x+2)=0\\
x=-\dfrac{3}{4} \vee x=1 \vee x=-2$

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The ideal mass for a piece of chocolate is 2.5 ounces. The actual mass for a production can vary by, at most, 0.08

Nady [450]

Answer:

$2.42\,oz \leq m_{real} \leq 2.58\,oz$

Step-by-step explanation:

The inequality must be the absolute value of the difference between real mass and ideal mass less or equal to 0.08 ounces. That is to say:

$|m_{real} - m_{ideal}| \leq 0.08\,oz$

$|m_{real} - 2.5\,oz| \leq 0.08\,oz$

There are two extreme cases:

$m_{real,max} - 2.5\,oz = 0.08\,oz$ and $m_{real, min} - 2.5\,oz = -0.08\,oz$

$m_{real, max} = 2.58\,oz$ and $m_{real,min} = 2.42\,oz$

Range of chocolate masses must be:

$m_{real, min} \leq m_{real} \leq m_{real,max}$

$2.42\,oz \leq m_{real} \leq 2.58\,oz$

8 0

3 years ago

If 0.000023 is expressed in the form 2.3*10n what is the value of n

Inga [223]

N = 5
Because you have to the decimal 5 places to the right.
0.000023 = 2.3×10^5

3 0

3 years ago

Guys i need help this is due by tomorrow!!

aivan3 [116]

Answer:

lets start with the division

10/10

3+2 . 1 - 1

5 . 1 - 1

5. 1 = 5

5 - 1 = 4

Step-by-step explanation:

4 0

3 years ago

Consider the quadratic equation below. 4x^2-5=3x+4 Determine the correct set-up for solving the equation using the quadratic for

Kipish [7]

4x²-5=3x+4
4x²-3x-9=0

x=(3±√((-3)²-4*4*-9))/2*4

x=3±√(9+144) /8

x=(3±√153) /8

x=⅜±√153/8

4 0

3 years ago

Can someone please solve these questions

k0ka [10]

1)

=> m∠2 = 2x +13
=> m∠1 = 4x - 1
Since YP angle bisector the angles with be equal to each other,

m∠1 = m∠2
2x + 13 = 4x - 1
2x - 4x = -1 -13
-2x = -14
x = 7

All other questions are to be done in that way, don't be lazy :P

6 0

3 years ago