Solve each polynomial equation by factoring 4x^3+7x^2-5x=6

1 answer:

3 0

$4x^3+7x^2-5x=6\\
4x^3+7x^2-5x-6=0\\
4x^3+8x^2-x^2-2x-3x-6=0\\
4x^2(x+2)-x(x+2)-3(x+2)=0\\
(4x^2-x-3)(x+2)=0\\
(4x^2-4x+3x-3)(x+2)=0\\
(4x(x-1)+3(x-1))(x+2)=0\\
(4x+3)(x-1)(x+2)=0\\
x=-\dfrac{3}{4} \vee x=1 \vee x=-2$

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Answer:

$f(x) = cos(x - \frac{\pi }{4} ) -1$

Step-by-step explanation:

In this graph, we have the coordinate point ( $\frac{\pi }{4} , 0$ ). Without translations, cos(0) = 0, which means that the graph is shifted to the right by $\frac{\pi }{4}$ . We also know that the graph is shifted down by 1 because we have the point

( $\frac{5\pi }{4} , -2$ ), but accounting for the right shift, this point should really by ( $\pi , -2$ ). cos( $\pi$ ) = -1, but on the graph it is -2, meaning that it is shifted down by 1.