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ella [17]
3 years ago
9

Which series of transformations results in the image being congruent to the pre-image?

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0

Answer:

.

Step-by-step explanation:

erik [133]3 years ago
4 0
For the element to be congruent only rotations, reflections or translations are allowed to be applied
1)
(x, y) → (x, –y)=reflection
(x, y) → (x + 5, y)=translation
(x, y) → (–x, y)=reflection
->is congruent
2)
(x, y) → (x + 1, y)=translation
(x, y) → (–x, –y)=reflection
(x, y) → (2x, y)=scaling->can't be congruent
3)
(x, y) → (0.5x, 0.5y)=scaling->can't be congruent
(x, y) → (x, –y)
(x, y) → (x, y + 8)
4)
(x, y) → (x – 4, y)=translation
(x, y) → (x, y + 3)=translation
(x, y) → (3x, 3y)=scaling->can't be congruent

so 1) is the only series of transformations with a congruent solution
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17p + 8p3 – 4 – 5(p3 – 2). Don't solve, I just need the simplest form
frutty [35]

Answer:

26p+6

Step-by-step explanation:

17p+8p3-4-5(p3-2)

opening the bracket and multiply by -5

=17p+8p3-4-5p3+10

taking a common factor p

=p[17+(8×3)-(5×3)]+6

solve the simple mathematical calculation

=26p+6

8 0
3 years ago
Which of the following equation describes the line shown below
pishuonlain [190]

Answer:

equation A describes the line

Step-by-step explanation:

(x,y) = (9,1)

1 -1 = (9-9) 5/3

or, 0 =0

4 0
3 years ago
c) The probability is 1% that an electrical connector that is kept dry fails during the warranty period of a portable computer.
Anni [7]

Answer: There is 0.014 proportion of connectors fail during the warranty period.

Step-by-step explanation:

Let A be the event that connector fails.

Let B be the event that connector wet.

P(B) = 10%

P(B') = 90%

P(A|B) = 0.05

P(A|B') = 0.01

So, we need to find the proportion of connectors fail during the warranty period is given by

P(A)=P(B)P(A|B)+P(B')P(A|B')\\\\P(A)=0.1\times 0.05+0.9\times 0.01\\\\P(A)=0.014

Hence, there is 0.014 proportion of connectors fail during the warranty period.

3 0
3 years ago
The gravitational force produced between any two objects kept 2.5×10^4 km apart is 580 N . At what distance should they be kept
DochEvi [55]

Answer:

Formula for gravitational force    F = G M1 * M2 / R^2  where G is the gravitational constant

F2 / F1 = (R1 / R2)^2 = 1/2         where F2 is the required force

R2 = (2)^1/2  R1     distance for R2 to be 1/2 force at R1

Since force is proportional to the square of the distance of separation, increasing the distance of separation by 2^2 will halve the force

7 0
3 years ago
Ravi is driving 440440 miles to visit his grandma. He drives at a rate of 5555 miles per hour. How many hours will it take him t
Elis [28]
The correct question is
Ravi<span> is </span>driving 440 miles<span> to </span>visit his grandma<span>. if </span>he drives<span> at an average </span>rate<span> of 55 miles </span>per hour<span>, how </span>many hours will<span> it </span>take him<span> to </span>get<span> 3/4 of the </span>way there<span>?
</span>
we have that
3/4 of the way--------------> (3/4)*440=330 miles

<span>I apply a rule of three
if 55 miles----------------> 1 hour
330 miles--------------> X
X=330/55=6 hour

the answer is 6 hour
</span>
7 0
3 years ago
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