Answer:
[PCl₃] = 0.031M
[Cl₂] = 0.031M
[PCl₅] = 0.969M
Explanation:
Based on the reaction:
PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)
<em>Where Keq = 1.0x10⁻³ = [PCl₃] [Cl₂] / [PCl₅]</em>
Inital [PCl₅] = 2.0mol / 2.0L = 1M.
In equilibrium:
[PCl₃] = X
[Cl₂] = X
[PCl₅] = 1M-X
<em>Where X is reaction coordinate</em>
<em />
Replacing:
1.0x10⁻³ = [X] [X] / [1-X]
1.0x10⁻³ - 1.0x10⁻³X = X²
1.0x10⁻³ - 1.0x10⁻³X - X² = 0
Solving for X:
X = -0.032M. False solution, there is no negative concentration
X = 0.031M
That means equlibrium concentrations are:
[PCl₃] = 0.031M
[Cl₂] = 0.031M
[PCl₅] = 1-0.031M = 0.969M
<h3>[PCl₃] = 0.031M</h3><h3>[Cl₂] = 0.031M</h3><h3>[PCl₅] = 0.969M</h3>
Answer:
By electroplating
Explanation:
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Explanation:
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The alcoholic can seek rehab