Answer:
b. has a low specific heat capacity.
Explanation:
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In this case, since the specific heat is defined as the heat required to increase or decrease 1 degree Celsius 1 gram or mole of a specific substance, we infer that the lower the specific heat, the less energy will be needed for such increase or decrease, therefore, it turns out easier to modify the temperature in a substance that b. has a low specific heat capacity.
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The true is that both substances will have 2 * 6.02* 10^23 = 12.04 * 10^23 particles (may be molucules or atoms(.
Also, the two moles of each substance will have different masses, because you have to multiply the number of moles of each substance by the respective molar mass (or atomic mass).
<span>CO2 = 1.580 grams
H2O = 0.592 grams
Lookup the molar mass of each element in the compound
Carbon = 12.0107
Hydrogen = 1.00794
Oxygen = 15.999
Calculate the molar mass of CH4O by adding the total masses of each element used.
12.0107 + 4 * 1.00794 + 15.999 = 32.04146
Now calculate how many moles of CH4O you have by dividing by the molar mass.
m = 1.15 g / 32.04146 g/mole = 0.035891 mole
Now figure out how many moles of carbon and hydrogen you have.
Carbon = 0.035891 moles
Hydrogen = 0.035891 moles * 4 = 0.143564 moles
For Carbon Dioxide, you need 2 moles of oxygen per mole of carbon. So the mass of the carbon dioxide will be
0.035891 * 12.0107 + 2 * 0.035891 * 15.999 = 1.579516 grams
For water, you need 1/2 mole of oxygen per mole of hydrogen. So the mass of H2o will be
0.035891 * 1.00794 / 2 + 0.035891 * 15.999 = 0.592308 grams</span>
Answer:
Sodium Bicarbonate on decomposition produces Carbon dioxide gas and Water vapors.
<span> 2 NaHCO</span>₂<span> </span> →<span> Na</span>₂<span>CO</span>₃<span> (s) </span>+ <span> CO</span>₂<span> (g) + H</span>₂<span>O (g)
</span>
Explanation:
Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.
Answer:c
Explanation: just took the test