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3 years ago

For an atom of chlorine-35, what number would you put as the SUPERSCRIPT in the atomic notation?

1 answer:

6 0

<h2>Answer:</h2><h3>CI.Strictly speaking,the subscript is unnecessary ,since all atoms of cholorine have 17 protons.Hence the isotope symbols are usually written withouth the subscript.³⁵CI and ³⁷CI</h3>

<h2>EXPLANATION:</h2><h2>I HPE IT HELP THANK YOU!</h2>

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When heat is applied to water a 10 degrees Celsius, what does the energy transform into?

LUCKY_DIMON [66]

Answer:

Gas

Explanation:

This is kind of like the process of evaporating

5 0

4 years ago

What does the peak of a probability curve for an electron in an atom indicate?

Eduardwww [97]

The distance from the nucleus at which the electron is most likely to be found

3 0

3 years ago

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Calculate %ic of the interatomic bonds for the intermetallic compound al6mn. on the basis of this result, what type of interatom

pashok25 [27]

Answer : % ionic character is 0.20%

Bonding between the two metals will be purely metallic.

Explanation: For the calculation of % ionic character, we use the formula

$\% \text{ ionic character}= [1-e^{\frac{-(X_A-X_B)^2)}{4}}]\times(100\%)$

where $X_A$ & $X_B$ are the Pauling's electronegativities.

The table attached has the values of electronegativities, by taking the values of Al and Mn from there,

$X_{Al}=1.61$

$X_{Mn}=1.55$

Putting the values in the electronegativity formula, we get

$\% \text{ ionic character}= [1-e^{\frac{-(1.61-1.55)^2)}{4}}]\times(100\%)$

= 0.20%

Now, there are 3 types of inter atomic bonding

1) Ionic Bonding: It refers to the chemical bond in which there is complete transfer of valence electrons between atoms

2) Covalent Bonding: It refers to the chemical bond involving the sharing of electron pairs between 2 atoms.

3) Metallic Bonding: It refers to the chemical bond in which there is an electrostatic force between the positively charged metal ions and delocalised electrons.

In $Al_6Mn$ compound, the % ionic character is minimal that is $\sim$ 0.20% and there are two metal ions present, therefore this compound will have metallic bonding.

8 0

3 years ago

Mg + 2HCl → MgCl2 + H2

deff fn [24]

Answer:

Explanation:

This is a limiting reactant problem.

Mg(s)

2HCl(aq)

→

MgCl

(

)

+ H

(

)

Determine Moles of Magnesium

Divide the given mass of magnesium by its molar mass (atomic weight on periodic table in g/mol).

4.86

g Mg

mol Mg

24.3050

g Mg

0.200 mol Mg

Determine Moles of 2M Hydrochloric Acid

Convert

100 cm

100 mL

and then to

0.1 L

1 dm

1 L

Convert

2.00 mol/dm

2.00 mol/L

Multiply

0.1

times

2.00 mol/L

100

1000

0.1 L HCl

2.00 mol/dm

2.00 mol/L

0.1

2.00

mol

0.200 mol HCl

Multiply the moles of each reactant times the appropriate mole ratio from the balanced equation. Then multiply times the molar mass of hydrogen gas,

2.01588 g/mol

0.200

mol Mg

mol H

mol Mg

2.01588

g H

mol H

0.403 g H

0.200

mol HCl

mol H

mol HCl

2.01588

g H

mol H

0.202 g H

The limiting reactant is

HCl

, which will produce

0.202 g H

under the stated conditions.

pls mark as brainliest ans

7 0

2 years ago

Read 2 more answers

When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati

babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

$MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}$

Here, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 1
Cl = 1

Number of atoms on product side are as follows.

Mn = 1
O = 1
H = 2
Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply $H_{2}O$ by 2 on product side. Therefore, the equation can be rewritten as follows.

$MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$

Hence, number of atoms on reactant side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Number of atoms on product side are as follows.

Mn = 1
O = 2
H = 4
Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is $MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}$ .

6 0

3 years ago