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andreyandreev [35.5K]
3 years ago
7

For an atom of chlorine-35, what number would you put as the SUPERSCRIPT in the atomic notation?

Chemistry
1 answer:
kobusy [5.1K]3 years ago
6 0
<h2>Answer:</h2><h3><em>C</em><em>I</em><em>.</em><em>S</em><em>t</em><em>r</em><em>i</em><em>c</em><em>t</em><em>l</em><em>y</em><em> </em><em>s</em><em>p</em><em>e</em><em>a</em><em>k</em><em>i</em><em>n</em><em>g</em><em>,</em><em>t</em><em>h</em><em>e</em><em> </em><em>s</em><em>u</em><em>b</em><em>s</em><em>c</em><em>r</em><em>i</em><em>p</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>u</em><em>n</em><em>n</em><em>e</em><em>c</em><em>e</em><em>s</em><em>s</em><em>a</em><em>r</em><em>y</em><em> </em><em>,</em><em>s</em><em>i</em><em>n</em><em>c</em><em>e</em><em> </em><em>a</em><em>l</em><em>l</em><em> </em><em>a</em><em>t</em><em>o</em><em>m</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>h</em><em>o</em><em>l</em><em>o</em><em>r</em><em>i</em><em>n</em><em>e</em><em> </em><em>h</em><em>a</em><em>v</em><em>e</em><em> </em><em>1</em><em>7</em><em> </em><em>p</em><em>r</em><em>o</em><em>t</em><em>o</em><em>n</em><em>s</em><em>.</em><em>H</em><em>e</em><em>n</em><em>c</em><em>e</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>i</em><em>s</em><em>o</em><em>t</em><em>o</em><em>p</em><em>e</em><em> </em><em>s</em><em>y</em><em>m</em><em>b</em><em>o</em><em>l</em><em>s</em><em> </em><em>a</em><em>r</em><em>e</em><em> </em><em>u</em><em>s</em><em>u</em><em>a</em><em>l</em><em>l</em><em>y</em><em> </em><em>w</em><em>r</em><em>i</em><em>t</em><em>t</em><em>e</em><em>n</em><em> </em><em>w</em><em>i</em><em>t</em><em>h</em><em>o</em><em>u</em><em>t</em><em>h</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>s</em><em>u</em><em>b</em><em>s</em><em>c</em><em>r</em><em>i</em><em>p</em><em>t</em><em>.</em><em>³</em><em>⁵</em><em>C</em><em>I</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>³</em><em>⁷</em><em>C</em><em>I</em></h3>

<h2><em><u>E</u></em><em><u>X</u></em><em><u>P</u></em><em><u>L</u></em><em><u>A</u></em><em><u>N</u></em><em><u>A</u></em><em><u>T</u></em><em><u>I</u></em><em><u>O</u></em><em><u>N</u></em><em><u>:</u></em></h2><h2><em>I</em><em> </em><em>H</em><em>P</em><em>E</em><em> </em><em>I</em><em>T</em><em> </em><em>H</em><em>E</em><em>L</em><em>P</em><em> </em><em>T</em><em>H</em><em>A</em><em>N</em><em>K</em><em> </em><em>Y</em><em>O</em><em>U</em><em>!</em></h2>

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Suppose 50.0g of silver nitrate is reacted with 50g of hydrochloric acid producing silver chloride and a mixture of other produc
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Answer:

53.6 grams of silver chloride was produced.

Explanation:

AgNO_3+HCl+\rightarrow AgCl+HNO_3

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

Mass of silver nitrate = 50.0 g

Mass of hydrogen chloride = 50.0 g

Mass of silver chloride = x

Mass of  nitric acid = 46.4 g

Mass of silver nitrate + Mass of hydrogen chloride =

                             Mass of silver chloride + Mass of  nitric acid

[te]50.0 g+50.0 g=x+46.4 g[/tex]

x=50.0 g+50.0 g - 46.4 g = 53.6 g

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  • <u><em>Because the x-intercet of the graph represents volume zero, which indicates the minimum possible temperature or absolute zero.</em></u>

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When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left  273.15ºC.

Meaning that the Volume at 273.15ºC is zero.

You cannot reach such low temperatures in an experiment, and also, volume zero is not real.

Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.

Subject to the experimental errors, and the fact that the real gases are not ideal, the temperature that you read on the x-axis is the minimum possible temperature (<em>absolute zero</em>) as the minimum possible volume is zero.

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