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vagabundo [1.1K]
3 years ago
11

If the function f has a continuous derivative on [0,c], then from 0 to c, integral f'(x) dx=?

Mathematics
1 answer:
Flura [38]3 years ago
5 0

Answer:

\int\limits^0_c f'(x) dx =f(c)-f(0)

Step-by-step explanation:

we are given

f has a continuous derivative on [0,c]

and we know that

derivative and integral are inverse of each other

so, we can write as

\int \:f'\left(x\right)dx=f\left(x\right)

we are given bound

so, we can use fundamental theorem of calculus

\int\limits^a_b f'(x) dx =f(b)-f(a)

we have bound from 0 to c

so, we get

\int\limits^0_c f'(x) dx =f(c)-f(0)

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The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

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Compute the probability of selecting a Spade second as follows:

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Then the probability that the first card is a Heart and the second card is a Spade is:

P(1st\  H\cap 2nd\ S)=P(H)\times P(S)

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Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

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