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Gemiola [76]
3 years ago
14

You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that t

he first card is a Heart and the second card is a Spade. Write your answer as a decimal rounded to four places if necessary.
Mathematics
1 answer:
icang [17]3 years ago
4 0

Answer:

The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

Spades (S) = 13

Hearts (H) = 13

Diamonds (D) = 13

Clubs (C) = 13

Compute the probability of selecting a Heart first as follows:

P(H)=\frac{13}{52}=0.25

Compute the probability of selecting a Spade second as follows:

P(S)=\frac{13}{51}=0.255

Since the two cards are selected without replacement the second draw is independent of the other.

Then the probability that the first card is a Heart and the second card is a Spade is:

P(1st\  H\cap 2nd\ S)=P(H)\times P(S)

                            =0.25\times 0.255\\=0.06375\\\approx 0.064

Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

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24 PTS!!!!!!1
balandron [24]

Answer:

  D  (7, 0.5)

Step-by-step explanation:

The equations must be interpreted to be ...

  • y = -1/2x +4
  • y = 1/2x -3

A graph shows the solution to be (7, 0.5), matching selection D.

___

You can add the two equations together to get ...

  (y) +(y) = (-1/2x +4) + (1/2x -3)

  2y = 1 . . . . . simplify

  y = 1/2 . . . . .divide by 2

It can be convenient to use the second equation to find x.

  1/2 = 1/2x - 3

  1 = x - 6 . . . . . . multiply by 2

  7 = x . . . . . . . . . add 6

The solution is (x, y) = (7, 0.5). . . . . matches selection D.

8 0
3 years ago
The Falcons had 3 fewer than twice as many Bears players. If the Falcons had 11 players, how many players were on the Bears?
Dmitry [639]
Subtraction, 11-3 is 8
Ps:trick question
3 0
2 years ago
An actor invests some money at 9​% simple​ interest, and ​$24,000 more than three times the amount at 10​% simple interest. The
Andrew [12]

Answer:

The amount invested at 9% is $93000

The amount invested at 10% is $303000

Step-by-step explanation:

Let the amount invested at 9% interest rate be x

And the amount invested at 10% rate be y

Simple Interest from x in a year = 0.09x

Simple Interest from y in a year = 0.1y

But y = 24000 + 3x

And the sun of the interests, 0.09x + 0.1y = 38670

Now we have a simultaneous eqn

y = 24000 + 3x (eqn 1)

0.09x + 0.1y = 38670 (eqn)

Substitute y into eqn 2

0.09x + 0.1(24000 + 3x) = 38670

0.09x + 2400 + 0.3x = 38670

0.39x = 38670 - 2400

x = 36270/0.39 = $93000

y = 24000 + 3x = 24000 + 3 × 93000 = $303000

8 0
3 years ago
Mr. Nolan has a bank account that compounds interest
german

Answer: At the end of the day on December 8, he has a total balance of $2841.02

Step-by-step explanation:

The rate at which the compound interest adds up is a 3.7%.

His principal is $2644.08, on the 7th of December, he withdraws $550. Thus, his balance is = $2644.08 - $550 = $2094.08.

He later deposits $934, after being paid by his employer.

That is $2094.08 + $934 = $3028.08

Which is his balance at the end of the day on December 7.

Remember that the rate is daily, at a 3.7%.

A 3.7% of the balance of December 7, $3028.08 is $112.039.

In total, interest +amount = real balance,

$112.039+$3028.08 = $3140.119

He later withdraws $300 for holiday shopping = $3140.119 - 300 = $2840.119

But 1 dollar = 100 cents and vice versa.

Therefore, $2840.119 = $2841.019

In two decimal places, that is approximately $2841.02

Therefore, Mr Nolan's balance at the end of December 8 is $2841.02.

4 0
3 years ago
3x - 2y + 3z = -20<br> 4x - 3y - 2z = 7<br> -5x + 5y + z = 9
skelet666 [1.2K]

Answer:

x= 4 y= 7 z= -6

Step-by-step explanation:

solve for one and you get them all

First, I got rid of the z by multiplying common factors (multiplied z by 2) and added equations 2 and 3 together after multiplying by 2

4x - 3y - 2z = 7

-10x+10y+2z= 18

-6x+7y= 25

Then multiplied z by -3 (to get rid of the z) with the original equation 3

3x - 2y + 3z = -20

15x-15y-3z= -27

18x-17y= -47

Next find common thing between the 2 equations we got and multiply it by that and combine (we can multiply first equation by 3 to get rid of the x and solve for y)

-18x+21y= 75

18x-17y= -47

y=7

Work backwards, substitute 7 into the above equation, you get x= 4 and then same for z to get z= -6

8 0
2 years ago
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