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ELEN [110]
3 years ago
14

The length of a rectangle is 3 inches longer than half of its width. The area of the

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

Width = 26 inches

Step-by-step explanation:

The area of the rectangle is:

area = (length*width)

416 = a*b

a = b/2  + 3

a = length

b = width

then:

416 = (b/2 + 3) (b)

416 = b*b/2 + b*3

416 = b²/2 + 3b

0 = b²/2 + 3b - 416

b = {-(+3)±√((3²)-(4*1/2*-416))} / (2*1/2)

b = {-3±√(9+832)} / 1

b = {-3±√841}

b = -3±29

only take the positive value becuse is a natural number

b = -3+29

b = 26 inches

a = b/2 + 3

a = 26/2 + 3

a = 13 + 3

a = 16 inches

Check:

416 = 16 * 26  

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Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

<h3>What is the range?</h3>

It is defined as the difference between the maximum value in the data set to the minimum value in the data set.

We have:

The amount of money in tips earned by four restaurant servers waiting on 10 tables is represented by the following data sets:

Alyssa {3, 6, 2, 8, 12, 14, 5, 7, 7, 8}

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The IQR for Alyssa:

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IQR = Q3 - Q1

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IQR = Q3 - Q1

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The IQR for Devon:

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IQR = 8 - 2 = 6

Thus, Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

Learn more about the range here:

brainly.com/question/17553524

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When Sherron inputs the equation 4x + 3 = 4(1 + x) + 1, she gets a<br> error message. Explain why.
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She gets

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Step-by-step explanation:

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