Answer:
the answer would be .5 miles
Step-by-step explanation:
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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The mass lost by Darragh's coin is 0.164 g
<u>Solution:</u>
Given that Darragh has a Golden Eagle coin in his collection with a mass of 13.551 g
An uncirculated Golden Eagle coin has a mass of 13.715 g
To find: mass lost by Darragh's coin
From given question,
Darrangh has coin of mass = 13.551 g
Golden Eagle coin mass = 13.715 g
Darrangh's coin lost mass = 13.715 - 13.551 = 0.164
Thus mass lost by Darragh's coin is 0.164 g
Answer: Choice B) -5.2 degrees
=====================
Work Shown:
Add up the given temperatures
-42 + (-17) + 14 + (-4) + 23 = -26
Then divide by 5 since there are 5 values we're given
-26/5 = -5.2
